A bag contains 3 red marbles, 5 blue marbles and 8 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1oth of a percent, that both marbles drawn will be blue? Answer:

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Calculate Total Marbles: Determine the total number of marbles in the bag. Add the number of red, blue, and green marbles together. 3 red + 5 blue + 8 green = 16 total marbles.Calculate Probability of Drawing: Calculate the probability of drawing one blue marble. Since there are 5 blue marbles out of 16 total marbles, the probability of drawing one blue marble is 5/16.Calculate Probability of Second Draw: Calculate the probability of drawing a second blue marble after one has already been drawn. After drawing one blue marble, there are now 4 blue marbles left and 15 marbles in total. The probability of drawing a second blue marble is now 4/15.Calculate Probability of Both Events: Calculate the probability of both events happening together (drawing two blue marbles in a row). Multiply the probabilities of each individual event to find the combined probability. (5/16) * (4/15) = 20/240 = 1/12.Convert Probability to Percentage: Convert the probability to a percentage. To convert a fraction to a percentage, multiply it by 100. (1/12) * 100 = 8.333...Round Percentage: Round the percentage to the nearest tenth of a percent. 8.333...% rounds to 8.3% when rounded to the nearest tenth of a percent.

A bag contains $3$ red marbles, $5$ blue marbles and $8$ green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest $1$ oth of a percent, that both marbles drawn will be blue? $\newline$ Answer:

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A bag contains $3$ red marbles, $5$ blue marbles and $8$ green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest $1$ oth of a percent, that both marbles drawn will be blue? $\newline$ Answer: