A bag contains 2 red marbles, 7 blue marbles and 4 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10ooth, that both marbles drawn will be red?Answer:
Q. A bag contains 2 red marbles, 7 blue marbles and 4 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10ooth, that both marbles drawn will be red?Answer:
Calculate Total Marbles: Given: A bag contains 2 red marbles, 7 blue marbles, and 4 green marbles. We need to calculate the probability of drawing 2 red marbles in succession without replacement.First, calculate the total number of marbles in the bag.Total marbles = 2 red + 7 blue + 4 greenTotal marbles = 13
First Red Marble Probability: Calculate the probability of drawing the first red marble.Probability of first red marble = Number of red marbles / Total number of marblesProbability of first red marble = 132
Second Red Marble Probability: Calculate the probability of drawing the second red marble after the first one has been drawn.Now there is 1 red marble left and the total number of marbles in the bag is 12.Probability of second red marble = Number of red marbles left / Total number of marbles leftProbability of second red marble =121
Combined Probability: Calculate the combined probability of both events happening one after the other (drawing two red marbles in succession).Combined probability = Probability of first red marble × Probability of second red marbleCombined probability = (132)×(121)Combined probability = 1562Combined probability = 781
Express Probability: To express the probability to the nearest thousandth, we can leave the fraction as is or convert it to a decimal.Probability to the nearest thousandth = 781≈0.013 (rounded to three decimal places)