Which of the following is an equation of the line in the xy plane with x-intercept 35 and y intercept 710 ?Choose 1 answer:(A) −7y+6x=10(B) 7y+6x=−10(C) 7y+6x=10(D) 7y−6x=10
Q. Which of the following is an equation of the line in the xy plane with x-intercept 35 and y intercept 710 ?Choose 1 answer:(A) −7y+6x=10(B) 7y+6x=−10(C) 7y+6x=10(D) 7y−6x=10
Finding Intercepts: The x-intercept of a line is the point where the line crosses the x-axis, which means the y-coordinate is 0. Similarly, the y-intercept is where the line crosses the y-axis, meaning the x-coordinate is 0. We can use these intercepts to find the equation of the line in the form of Ax+By=C, where A, x0, and x1 are constants.
Substituting x-intercept: Given the x-intercept (35,0), we can substitute x=35 and y=0 into the equation Ax+By=C to find the relationship between A and C. A(35)+B(0)=C 35A=C
Substituting y-intercept: Given the y-intercept(0,710), we can substitute x=0 and y=710 into the equation Ax+By=C to find the relationship between B and C. A(0)+B(710)=C 710B=C
Equating the expressions for C: We now have two equations relating A, B, and C:35A=C710B=CWe can equate these two expressions for C to find the relationship between A and B.35A=710BMultiplying both sides by 21 (the least common multiple of 3 and 7) to clear the fractions, we get:35A=30B
Solving for A and B: To find A and B, we can choose a common multiple of 35 and 30 that will make A and Bintegers. The smallest such number is 210, so we can set 35A=210 and 30B=210. Solving for A and B gives us:B1B2
Solving for C: Now that we have A and B, we can use either of the two equations we found earlier to solve for C: 35A=C 35(6)=C C=10
Final Equation: We have found A=6, B=7, and C=10. The equation of the line is therefore:6x+7y=10
Comparing with answer choices: We can now compare the equation we found with the answer choices given:(A) −7y+6x=10(B) 7y+6x=−10(C) 7y+6x=10(D) 7y−6x=10The correct equation that matches our derived equation is (C) 7y+6x=10.
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