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Which of the following expressions is equivalent to 
(9n)/(45 n+9) ?
Choose 1 answer:
(A) 
(1)/(6)
(B) 
(n)/(5n+1)
(c) 
(n)/(5n+9)
(D) 
(n)/(45 n+1)

Which of the following expressions is equivalent to 9n45n+9 \frac{9 n}{45 n+9} ?\newlineChoose 11 answer:\newline(A) 16 \frac{1}{6} \newline(B) n5n+1 \frac{n}{5 n+1} \newline(C) n5n+9 \frac{n}{5 n+9} \newline(D) n45n+1 \frac{n}{45 n+1}

Full solution

Q. Which of the following expressions is equivalent to 9n45n+9 \frac{9 n}{45 n+9} ?\newlineChoose 11 answer:\newline(A) 16 \frac{1}{6} \newline(B) n5n+1 \frac{n}{5 n+1} \newline(C) n5n+9 \frac{n}{5 n+9} \newline(D) n45n+1 \frac{n}{45 n+1}
  1. Factor out the greatest common factor: Simplify the expression by factoring out the greatest common factor in the numerator and the denominator.\newlineThe greatest common factor of 9n9n and 45n+945n+9 is 99.\newlineSo, we factor out 99 from the denominator.\newline9n45n+9\frac{9n}{45n+9} = 9n9(5n+1)\frac{9n}{9(5n+1)}
  2. Cancel out the common factor: Cancel out the common factor of 99 in the numerator and the denominator.\newline9n9(5n+1)=n5n+1\frac{9n}{9(5n+1)} = \frac{n}{5n+1}

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