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Which of the following expressions is equivalent to 
(-5k-10)/(40 k+45) ?
Choose 1 answer:
(A) 
(k+2)/(8k+9)
(B) 
(-k-2)/(8k-9)
(C) 
(-k-2)/(8k+9)
(D) 
(-k+2)/(8k+9)

Which of the following expressions is equivalent to 5k1040k+45 \frac{-5 k-10}{40 k+45} ?\newlineChoose 11 answer:\newline(A) k+28k+9 \frac{k+2}{8 k+9} \newline(B) k28k9 \frac{-k-2}{8 k-9} \newline(C) k28k+9 \frac{-k-2}{8 k+9} \newline(D) k+28k+9 \frac{-k+2}{8 k+9}

Full solution

Q. Which of the following expressions is equivalent to 5k1040k+45 \frac{-5 k-10}{40 k+45} ?\newlineChoose 11 answer:\newline(A) k+28k+9 \frac{k+2}{8 k+9} \newline(B) k28k9 \frac{-k-2}{8 k-9} \newline(C) k28k+9 \frac{-k-2}{8 k+9} \newline(D) k+28k+9 \frac{-k+2}{8 k+9}
  1. Factor out common factors: Factor out the greatest common factor in the numerator and the denominator.\newlineThe greatest common factor in the numerator is 55, and in the denominator, it is 55 as well. Let's factor them out.\newline(5k10)(-5k - 10) can be factored as 5(k+2)-5(k + 2).\newline(40k+45)(40k + 45) can be factored as 5(8k+9)5(8k + 9).\newlineSo, the expression becomes:\newline5(k+2)5(8k+9) \frac{-5(k + 2)}{5(8k + 9)}
  2. Simplify expression: Simplify the expression by canceling out the common factors.\newlineThe 5-5 in the numerator and the 55 in the denominator can be canceled out because they are common factors.\newlineThis simplification gives us:\newline(k+2)(8k+9)-\frac{(k + 2)}{(8k + 9)}
  3. Check answer choices: Check the answer choices to see which one matches our simplified expression.\newlineThe expression we have is k+28k+9-\frac{{k + 2}}{{8k + 9}}, which matches choice (C).

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