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When Li Juan's auto yard is filled to capacity with only cars, it has 60 cars. When it is filled to capacity with only vans, it has 50 vans. Which linear equation models the number of cars, 
c, and vans, 
v, that could be in Li Juan's auto yard when it is filled to capacity?
Choose 1 answer:
(A) 
(c)/( 60)+(v)/( 50)=1
(B) 
60 c+50 v=1
(c) 
(c)/( 50)+(v)/( 60)=1
(D) 
50 c+60 v=1

When Li Juan's auto yard is filled to capacity with only cars, it has 6060 cars. When it is filled to capacity with only vans, it has 5050 vans. Which linear equation models the number of cars, c c , and vans, v v , that could be in Li Juan's auto yard when it is filled to capacity?\newlineChoose 11 answer:\newline(A) c60+v50=1 \frac{c}{60}+\frac{v}{50}=1 \newline(B) 60c+50v=1 60 c+50 v=1 \newline(C) c50+v60=1 \frac{c}{50}+\frac{v}{60}=1 \newline(D) 50c+60v=1 50 c+60 v=1

Full solution

Q. When Li Juan's auto yard is filled to capacity with only cars, it has 6060 cars. When it is filled to capacity with only vans, it has 5050 vans. Which linear equation models the number of cars, c c , and vans, v v , that could be in Li Juan's auto yard when it is filled to capacity?\newlineChoose 11 answer:\newline(A) c60+v50=1 \frac{c}{60}+\frac{v}{50}=1 \newline(B) 60c+50v=1 60 c+50 v=1 \newline(C) c50+v60=1 \frac{c}{50}+\frac{v}{60}=1 \newline(D) 50c+60v=1 50 c+60 v=1
  1. Maximum Capacity of Auto Yard: Let's consider the maximum capacity of the auto yard in terms of space. When filled with cars, the yard holds 6060 cars, and when filled with vans, it holds 5050 vans. We can assume that each car takes up the same amount of space, and each van takes up the same amount of space. However, the space taken by a car is not necessarily the same as the space taken by a van.
  2. Relationship between Cars and Vans: We need to find a relationship between the number of cars and vans that can fit in the yard when it is at full capacity. Since the yard can hold 6060 cars, we can say that 11 car takes up 160\frac{1}{60} of the yard's capacity. Similarly, since the yard can hold 5050 vans, 11 van takes up 150\frac{1}{50} of the yard's capacity.
  3. Fraction of Yard's Capacity: If we have cc cars in the yard, they would take up c60\frac{c}{60} of the yard's capacity. Similarly, if we have vv vans in the yard, they would take up v50\frac{v}{50} of the yard's capacity. The sum of these two fractions should equal 11, because together they fill the yard to capacity.
  4. Equation for Capacity Relationship: The equation that represents this relationship is (c60)+(v50)=1(\frac{c}{60}) + (\frac{v}{50}) = 1. This equation states that the fraction of the yard's capacity taken up by cars plus the fraction taken up by vans equals the entire capacity of the yard.
  5. Matching Answer Choice: Looking at the answer choices, we can see that option (A) matches our derived equation: (c60)+(v50)=1(\frac{c}{60}) + (\frac{v}{50}) = 1.

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