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What is 
y-8=3(x+1) written in standard form?
Choose 1 answer:
(A) 
-3x+y-11=0
(B) 
y=3x+11
(c) 
y-8=3x+3
(D) 
-3x+y=11

What is y8=3(x+1) y-8=3(x+1) written in standard form?\newlineChoose 11 answer:\newline(A) 3x+y11=0 -3 x+y-11=0 \newline(B) y=3x+11 y=3 x+11 \newline(C) y8=3x+3 y-8=3 x+3 \newline(D) 3x+y=11 -3 x+y=11

Full solution

Q. What is y8=3(x+1) y-8=3(x+1) written in standard form?\newlineChoose 11 answer:\newline(A) 3x+y11=0 -3 x+y-11=0 \newline(B) y=3x+11 y=3 x+11 \newline(C) y8=3x+3 y-8=3 x+3 \newline(D) 3x+y=11 -3 x+y=11
  1. Distribute the 33: Distribute the 33 to both terms inside the parentheses.y8=3(x+1)y - 8 = 3(x + 1)y8=3x+3y - 8 = 3x + 3
  2. Add 88 to both sides: Add 88 to both sides to move the constant term to the right side of the equation.\newliney8+8=3x+3+8y - 8 + 8 = 3x + 3 + 8\newliney=3x+11y = 3x + 11
  3. Move x-term to same side: To write the equation in standard form Ax+By=CAx + By = C, we need to move the x-term to the same side as the y-term.\newlineSubtract 3x3x from both sides of the equation.\newline3x+y=11-3x + y = 11
  4. Check coefficients and x-term: Check if the coefficients are integers and the x-term is positive. If not, multiply the entire equation by 1-1.\newlineIn this case, the x-term is negative, so we multiply the entire equation by 1-1 to make the x-term positive.\newline1(3x+y)=1(11)-1(-3x + y) = -1(11)\newline3xy=113x - y = -11
  5. Multiply equation by 1-1: To get the standard form Ax+By=CAx + By = C, where AA, BB, and CC are integers, and AA is non-negative, we need to multiply the equation by 1-1 again because the standard form requires AA to be non-negative.\newline1(3xy)=1(11)-1(3x - y) = -1(-11)\newline3x+y=11-3x + y = 11

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