Q. What is y+5=7(x−8) written in standard form?Choose 1 answer:(A) 7x+y=−61(B) −7x+y=−61(C) x−7y=−61(D) x+7y=−61
Distribute to both terms: First, distribute the 777 to both terms inside the parentheses.\newliney + 555 = 777(x - 888)\newliney + 555 = 777x - 565656
Subtract 555 from both sides: Next, subtract 555 from both sides to get y by itself on one side.\newliney = 777x - 565656 - 555\newliney = 777x - 616161
Move xxx-term to the same side as yyy-term: Now, to write the equation in standard form, Ax+By=CAx + By = CAx+By=C, we need to move the xxx-term to the same side as the yyy-term.\newlineSubtract 7x7x7x from both sides to achieve this.\newline−7x+y=−61-7x + y = -61−7x+y=−61
Make coefficient of x positive: The standard form of a linear equation is Ax+By=CAx + By = CAx+By=C, where AAA is a positive integer. Since −7-7−7 is negative, we can multiply the entire equation by −1-1−1 to make the coefficient of x positive.\newline−1(−7x+y)=−1(−61)-1(-7x + y) = -1(-61)−1(−7x+y)=−1(−61)\newline7x−y=617x - y = 617x−y=61
Rearrange terms to have x first: Finally, to match the standard form exactly, we need to rearrange the terms to have x first, then y.\newline7x−y=617x - y = 617x−y=61
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