What is y+5=7(x-8) written in standard form? Choose 1 answer: (A) -7x+y=-61 (B) x-7y=-61 (c) 7x+y=-61 (D) x+7y=-61

Distribute 7 to both terms: First, distribute the 7 to both terms inside the parentheses. y + 5 = 7(x - 8) y + 5 = 7x - 56Subtract 5 from both sides: Next, subtract 5 from both sides to get y by itself on one side. y = 7x - 56 - 5 y = 7x - 61Move x-term to the same side: Now, to write the equation in standard form, Ax + By = C, we need to move the x-term to the same side as the y-term. Subtract 7x from both sides. -7x + y = -61Check the answer choices: Check the answer choices to see which one matches our equation. (A) -7x + y = -61 is the correct standard form that matches our equation.

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What is
y+5=7(x-8) written in standard form?
Choose 1 answer:
(A)
-7x+y=-61
(B)
x-7y=-61
(c)
7x+y=-61
(D)
x+7y=-61

What is $y+5=7(x-8)$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $-7 x+y=-61$ $\newline$ (B) $x-7 y=-61$ $\newline$ (C) $7 x+y=-61$ $\newline$ (D) $x+7 y=-61$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

Q. What is

y+5=7(x-8)

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

-7 x+y=-61

\newline

(B)

x-7 y=-61

\newline

(C)

7 x+y=-61

\newline

(D)

x+7 y=-61

Distribute $7$ to both terms: First, distribute the $7$ to both terms inside the parentheses. $\newline$ $y +$ $5$ = $7$ (x - $8$ ) $\newline$ $y +$ $5$ = $7$ x - $56$
Subtract $5$ from both sides: Next, subtract $5$ from both sides to get $y$ by itself on one side. $\newline$ $y =$ $7$ x - $56$ - $5$ $\newline$ $y =$ $7$ x - $61$
Move $x$ -term to the same side: Now, to write the equation in standard form, $Ax + By = C$ , we need to move the $x$ -term to the same side as the $y$ -term. Subtract $7x$ from both sides. $\newline$ $-7x + y = -61$
Check the answer choices: Check the answer choices to see which one matches our equation. $\newline$ (A) $-7x + y = -61$ is the correct standard form that matches our equation.