What is y+4=-6(x+6) written in standard form? Choose 1 answer: (A) y=-6x+2 (B) 6x+y=-40 (C) 6x+y=2 (D) y=-6x-40

Distribute -6 across parentheses: First, we need to distribute the -6 across the parentheses on the right side of the equation. y + 4 = -6(x + 6) y + 4 = -6x - 36Subtract 4 from both sides: Next, we need to subtract 4 from both sides to get the y term by itself on the left side. y + 4 - 4 = -6x - 36 - 4 y = -6x - 40Write equation in standard form: Now, we need to write the equation in standard form, which is Ax + By = C, where A, B, and C are integers, and A should be non-negative. To do this, we add 6x to both sides of the equation. 6x + y = -40Check for non-negative coefficient and integer terms: We check to make sure that the coefficient of x is non-negative, which it is, and that all terms are integers, which they are. So the equation is now in standard form.

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What is
y+4=-6(x+6) written in standard form?
Choose 1 answer:
(A)
y=-6x+2
(B)
6x+y=-40
(C)
6x+y=2
(D)
y=-6x-40

What is $y+4=-6(x+6)$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $y=-6 x+2$ $\newline$ (B) $6 x+y=-40$ $\newline$ (C) $6 x+y=2$ $\newline$ (D) $y=-6 x-40$

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Algebra 2

Evaluate rational expressions II

Full solution

Q. What is

y+4=-6(x+6)

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

y=-6 x+2

\newline

(B)

6 x+y=-40

\newline

(C)

6 x+y=2

\newline

(D)

y=-6 x-40

Distribute $-6$ across parentheses: First, we need to distribute the $-6$ across the parentheses on the right side of the equation. $y + 4 = -6(x + 6)$ $y + 4 = -6x - 36$
Subtract $4$ from both sides: Next, we need to subtract $4$ from both sides to get the $y$ term by itself on the left side. $\newline$ $y + 4 - 4 = -6x - 36 - 4$ $\newline$ $y = -6x - 40$
Write equation in standard form: Now, we need to write the equation in standard form, which is $Ax + By = C$ , where $A$ , $B$ , and $C$ are integers, and $A$ should be non-negative. $\newline$ To do this, we add $6x$ to both sides of the equation. $\newline$ $6x + y = -40$
Check for non-negative coefficient and integer terms: We check to make sure that the coefficient of $x$ is non-negative, which it is, and that all terms are integers, which they are. So the equation is now in standard form.