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What is 
y+4=-6(x+6) written in standard form?
Choose 1 answer:
(A) 
y=-6x-40
(B) 
6x+y=-40
(C) 
6x+y=2
(D) 
y=-6x+2

What is y+4=6(x+6) y+4=-6(x+6) written in standard form?\newlineChoose 11 answer:\newline(A) y=6x40 y=-6 x-40 \newline(B) 6x+y=40 6 x+y=-40 \newline(C) 6x+y=2 6 x+y=2 \newline(D) y=6x+2 y=-6 x+2

Full solution

Q. What is y+4=6(x+6) y+4=-6(x+6) written in standard form?\newlineChoose 11 answer:\newline(A) y=6x40 y=-6 x-40 \newline(B) 6x+y=40 6 x+y=-40 \newline(C) 6x+y=2 6 x+y=2 \newline(D) y=6x+2 y=-6 x+2
  1. Rephrasing the equation: First, let's rephrase the "What is the equation y+4=6(x+6)y+4=-6(x+6) written in standard form?"
  2. Distributing the 6 -6 : Now, let's distribute the 6 -6 across the (x+6) (x+6) in the equation y+4=6(x+6) y+4=-6(x+6) .y+4=6×x6×6 y + 4 = -6 \times x - 6 \times 6 y+4=6x36 y + 4 = -6x - 36
  3. Isolating y on one side: Next, we need to subtract 44 from both sides to isolate yy on one side.\newliney+44=6x364y + 4 - 4 = -6x - 36 - 4\newliney=6x40y = -6x - 40
  4. Converting to standard form: The equation y=6x40y = -6x - 40 is in slope-intercept form. To write it in standard form, we need to rearrange it so that all terms are on one side and the xx term is positive.\newlineAdd 6x6x to both sides:\newline6x+y=406x + y = -40
  5. Final equation in standard form: The equation 6x+y=406x + y = -40 is now in standard form with the xx term positive, which matches answer choice (B)(B).

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