What is y=(4)/(5)x+2 written in standard form? Choose 1 answer: (A) y=(4)/(5)(x+(5)/(2)) (B) -4x+5y=10 (C) -(4)/(5)x+y-2=0 (D) 5y=4x+10

Understanding the goal: Understand the goal. We need to rewrite the equation y=(4/5)x+2 in standard form. The standard form of a linear equation is Ax + By = C, where A, B, and C are integers, and A should be non-negative.Eliminating the fraction: Multiply both sides of the equation by 5 to eliminate the fraction. 5y = 5 * ((4/5)x + 2) 5y = 4x + 10Moving the x term: Move the term with x to the left side of the equation to get terms with variables on one side and constants on the other. 5y - 4x = 10Rearranging to standard form: Rearrange the terms to match the standard form Ax + By = C. -4x + 5y = 10Checking the coefficient of x: Check if the coefficient of x is non-negative. If it is negative, we can multiply the entire equation by -1 to make it non-negative. However, this is not strictly necessary as some definitions of standard form allow for a negative A.Verifying standard form and coefficients: Verify that the equation is in standard form and that all the coefficients are integers. The equation -4x + 5y = 10 is in standard form, and all coefficients are integers.

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What is
y=(4)/(5)x+2 written in standard form?
Choose 1 answer:
(A)
y=(4)/(5)(x+(5)/(2))
(B)
-4x+5y=10
(C)
-(4)/(5)x+y-2=0
(D)
5y=4x+10

What is $y=\frac{4}{5} x+2$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $y=\frac{4}{5}\left(x+\frac{5}{2}\right)$ $\newline$ (B) $-4 x+5 y=10$ $\newline$ (C) $-\frac{4}{5} x+y-2=0$ $\newline$ (D) $5 y=4 x+10$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

Q. What is

y=\frac{4}{5} x+2

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

y=\frac{4}{5}\left(x+\frac{5}{2}\right)

\newline

(B)

-4 x+5 y=10

\newline

(C)

-\frac{4}{5} x+y-2=0

\newline

(D)

5 y=4 x+10

Understanding the goal: Understand the goal. $\newline$ We need to rewrite the equation $y=\frac{4}{5}x+2$ in standard form. The standard form of a linear equation is $Ax + By = C$ , where $A$ , $B$ , and $C$ are integers, and $A$ should be non-negative.
Eliminating the fraction: Multiply both sides of the equation by $5$ to eliminate the fraction. $\newline$ $5y = 5 \times \left(\frac{4}{5}x + 2\right)$ $\newline$ $5y = 4x + 10$
Moving the $x$ term: Move the term with $x$ to the left side of the equation to get terms with variables on one side and constants on the other. $\newline$ $5y - 4x = 10$
Rearranging to standard form: Rearrange the terms to match the standard form $Ax + By = C$ . $\newline$ $-4x + 5y = 10$
Checking the coefficient of $x$ : Check if the coefficient of $x$ is non-negative. If it is negative, we can multiply the entire equation by $-1$ to make it non-negative. However, this is not strictly necessary as some definitions of standard form allow for a negative $A$ .
Verifying standard form and coefficients: Verify that the equation is in standard form and that all the coefficients are integers. $\newline$ The equation $-4x + 5y = 10$ is in standard form, and all coefficients are integers.