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What is 
y+3=7(x-2) written in standard form?
Choose 1 answer:
(A) 
y=7x-5
(B) 
-7x+y=-5
(C) 
y=7x-17
(D) 
-7x+y=-17

What is y+3=7(x2) y+3=7(x-2) written in standard form?\newlineChoose 11 answer:\newline(A) y=7x5 y=7 x-5 \newline(B) 7x+y=5 -7 x+y=-5 \newline(C) y=7x17 y=7 x-17 \newline(D) 7x+y=17 -7 x+y=-17

Full solution

Q. What is y+3=7(x2) y+3=7(x-2) written in standard form?\newlineChoose 11 answer:\newline(A) y=7x5 y=7 x-5 \newline(B) 7x+y=5 -7 x+y=-5 \newline(C) y=7x17 y=7 x-17 \newline(D) 7x+y=17 -7 x+y=-17
  1. Distribute 77 to both terms: First, we need to distribute the 77 to both terms inside the parentheses on the right side of the equation.\newliney+3=7(x2)y + 3 = 7(x - 2)\newliney+3=7x14y + 3 = 7x - 14
  2. Subtract 33 from both sides: Next, we need to subtract 33 from both sides to move the constant term to the right side of the equation.\newliney+33=7x143y + 3 - 3 = 7x - 14 - 3\newliney=7x17y = 7x - 17
  3. Write equation in standard form: Now, we need to write the equation in standard form, which is Ax+By=CAx + By = C. To do this, we subtract 7x7x from both sides to get the xx term on the left side.\newline7x+y=17-7x + y = -17
  4. Check answer choices: Finally, we check the answer choices to see which one matches our equation in standard form.\newline(A) y=7x5y = 7x - 5 (This is not in standard form.)\newline(B) 7x+y=5-7x + y = -5 (This does not match our equation.)\newline(C) y=7x17y = 7x - 17 (This is not in standard form.)\newline(D) 7x+y=17-7x + y = -17 (This matches our equation in standard form.)

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