What is y=-(3)/(10)x-8 written in standard form? Choose 1 answer: (A) 10 x+3y=-80 (B) 3x+10 y=-80 (c) -3x+10 y=-80 (D) 10 x-3y=-80

Multiply by 10: Multiply both sides of the equation by 10 to eliminate the fraction. 10 * y = 10 * (-(3)/(10)x - 8)Distribute 10: Distribute 10 to both terms on the right side of the equation. 10y = -3x - 80Rearrange equation: Rearrange the equation to get all variables on one side and constants on the other to achieve the standard form Ax + By = C. Add 3x to both sides of the equation. 3x + 10y = -80

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What is
y=-(3)/(10)x-8 written in standard form?
Choose 1 answer:
(A)
10 x+3y=-80
(B)
3x+10 y=-80
(c)
-3x+10 y=-80
(D)
10 x-3y=-80

What is $y=-\frac{3}{10} x-8$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $10 x+3 y=-80$ $\newline$ (B) $3 x+10 y=-80$ $\newline$ (C) $-3 x+10 y=-80$ $\newline$ (D) $10 x-3 y=-80$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

Q. What is

y=-\frac{3}{10} x-8

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

10 x+3 y=-80

\newline

(B)

3 x+10 y=-80

\newline

(C)

-3 x+10 y=-80

\newline

(D)

10 x-3 y=-80

Multiply by $10$ : Multiply both sides of the equation by $10$ to eliminate the fraction. $\newline$ $10 \cdot y = 10 \cdot \left(-\frac{3}{10}x - 8\right)$
Distribute $10$ : Distribute $10$ to both terms on the right side of the equation. $\newline$ $10y = -3x - 80$
Rearrange equation: Rearrange the equation to get all variables on one side and constants on the other to achieve the standard form $Ax + By = C$ . $\newline$ Add $3x$ to both sides of the equation. $\newline$ $3x + 10y = -80$