What is y=-(3)/(10)x-8 written in standard form? Choose 1 answer: (A) 10 x-3y=-80 (B) 10 x+3y=-80 (c) 3x+10 y=-80 (D) -3x+10 y=-80

Understand the goal: Understand the goal. We need to rewrite the equation y = -(3/10)x - 8 in standard form. The standard form of a linear equation is Ax + By = C, where A, B, and C are integers, and A should be non-negative.Multiply by 10: Multiply both sides of the equation by 10 to eliminate the fraction. 10 * y = 10 * (-(3/10)x - 8) This gives us: 10y = -3x - 80Move term with x: Move the term with x to the left side of the equation. To do this, we add 3x to both sides of the equation: 3x + 10y = -80Check coefficients: Check the coefficients to ensure they are integers and that the coefficient of x is non-negative. The coefficients are 3, 10, and -80, which are all integers, and the coefficient of x is positive, which is acceptable in standard form.

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What is
y=-(3)/(10)x-8 written in standard form?
Choose 1 answer:
(A)
10 x-3y=-80
(B)
10 x+3y=-80
(c)
3x+10 y=-80
(D)
-3x+10 y=-80

What is $y=-\frac{3}{10} x-8$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $10 x-3 y=-80$ $\newline$ (B) $10 x+3 y=-80$ $\newline$ (C) $3 x+10 y=-80$ $\newline$ (D) $-3 x+10 y=-80$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

Q. What is

y=-\frac{3}{10} x-8

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

10 x-3 y=-80

\newline

(B)

10 x+3 y=-80

\newline

(C)

3 x+10 y=-80

\newline

(D)

-3 x+10 y=-80

Understand the goal: Understand the goal. $\newline$ We need to rewrite the equation $y = -\left(\frac{3}{10}\right)x - 8$ in standard form. The standard form of a linear equation is $Ax + By = C$ , where $A$ , $B$ , and $C$ are integers, and $A$ should be non-negative.
Multiply by $10$ : Multiply both sides of the equation by $10$ to eliminate the fraction. $\newline$ $10 \cdot y = 10 \cdot (-(\frac{3}{10})x - 8)$ $\newline$ This gives us: $\newline$ $10y = -3x - 80$
Move term with x: Move the term with x to the left side of the equation. $\newline$ To do this, we add $3x$ to both sides of the equation: $\newline$ $3x + 10y = -80$
Check coefficients: Check the coefficients to ensure they are integers and that the coefficient of $x$ is non-negative. $\newline$ The coefficients are $3$ , $10$ , and $-80$ , which are all integers, and the coefficient of $x$ is positive, which is acceptable in standard form.