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What is 
y-2=-3(x-7) written in standard form?
Choose 1 answer:
(A) 
y=-3x+23
(B) 
3x+y=23
(C) 
y-2=-3x+21
(D) 
3x+y-23=0

What is y2=3(x7) y-2=-3(x-7) written in standard form?\newlineChoose 11 answer:\newline(A) y=3x+23 y=-3 x+23 \newline(B) 3x+y=23 3 x+y=23 \newline(C) y2=3x+21 y-2=-3 x+21 \newline(D) 3x+y23=0 3 x+y-23=0

Full solution

Q. What is y2=3(x7) y-2=-3(x-7) written in standard form?\newlineChoose 11 answer:\newline(A) y=3x+23 y=-3 x+23 \newline(B) 3x+y=23 3 x+y=23 \newline(C) y2=3x+21 y-2=-3 x+21 \newline(D) 3x+y23=0 3 x+y-23=0
  1. Distribute the 3-3: Distribute the 3-3 across the parentheses in the equation y2=3(x7)y-2=-3(x-7).\newliney2=3×x+3×7y - 2 = -3 \times x + 3 \times 7\newliney2=3x+21y - 2 = -3x + 21
  2. Add 22 to both sides: Add 22 to both sides of the equation to isolate y on one side.\newliney - 22 + 22 = 3-3x + 2121 + 22\newliney = 3-3x + 2323
  3. Move x-term to left side: To write the equation in standard form, Ax+By=CAx + By = C, we need to move the x-term to the left side of the equation.\newlineAdd 3x3x to both sides of the equation.\newline3x+y=3x3x+233x + y = 3x - 3x + 23\newline3x+y=233x + y = 23
  4. Check standard form: Check if the equation is in standard form, which requires AA, BB, and CC to be integers, and AA should be non-negative.\newlineThe equation 3x+y=233x + y = 23 satisfies these conditions, so it is in standard form.

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