What is y=(2)/(3)x+4 written in standard form? Choose 1 answer: (A) y-(2)/(3)x-4=0 (B) -2x+3y=12 (C) 3y=2x+12 (D) y=(2)/(3)(x+6)

Understanding the goal: Understand the goal. We need to rewrite the equation y=(2/3)x+4 in standard form. The standard form of a linear equation is Ax + By = C, where A, B, and C are integers, and A should be non-negative.Eliminating the fraction: Multiply both sides of the equation by 3 to eliminate the fraction. 3y = 3 * ((2/3)x + 4) This gives us 3y = 2x + 12.Rearranging the equation: Rearrange the equation to get all terms involving variables on one side and constants on the other. To do this, we subtract 2x from both sides to get: -2x + 3y = 12Checking the coefficient of x: Check if the coefficient of x is non-negative. In standard form, the coefficient of x should be non-negative. Since -2 is negative, we multiply the entire equation by -1 to make it positive. This gives us: 2x - 3y = -12Matching the standard form: Rearrange the terms to match the standard form Ax + By = C. The equation 2x - 3y = -12 is already in the correct form, but to match the standard form convention, we should write it as: 2x - 3y = -12

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What is
y=(2)/(3)x+4 written in standard form?
Choose 1 answer:
(A)
y-(2)/(3)x-4=0
(B)
-2x+3y=12
(C)
3y=2x+12
(D)
y=(2)/(3)(x+6)

What is $y=\frac{2}{3} x+4$ written in standard form? $\newline$ Choose $1$ answer: $\newline$ (A) $y-\frac{2}{3} x-4=0$ $\newline$ (B) $-2 x+3 y=12$ $\newline$ (C) $3 y=2 x+12$ $\newline$ (D) $y=\frac{2}{3}(x+6)$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

Q. What is

y=\frac{2}{3} x+4

written in standard form?

\newline

Choose

1

answer:

\newline

(A)

y-\frac{2}{3} x-4=0

\newline

(B)

-2 x+3 y=12

\newline

(C)

3 y=2 x+12

\newline

(D)

y=\frac{2}{3}(x+6)

Understanding the goal: Understand the goal. $\newline$ We need to rewrite the equation $y=\frac{2}{3}x+4$ in standard form. The standard form of a linear equation is $Ax + By = C$ , where $A$ , $B$ , and $C$ are integers, and $A$ should be non-negative.
Eliminating the fraction: Multiply both sides of the equation by $3$ to eliminate the fraction. $\newline$ $3y = 3 \times \left(\frac{2}{3}x + 4\right)$ $\newline$ This gives us $3y = 2x + 12$ .
Rearranging the equation: Rearrange the equation to get all terms involving variables on one side and constants on the other. $\newline$ To do this, we subtract $2x$ from both sides to get: $\newline$ $-2x + 3y = 12$
Checking the coefficient of $x$ : Check if the coefficient of $x$ is non-negative. $\newline$ In standard form, the coefficient of $x$ should be non-negative. Since $-2$ is negative, we multiply the entire equation by $-1$ to make it positive. $\newline$ This gives us: $\newline$ $2$ x - $3$ y = $-12$
Matching the standard form: Rearrange the terms to match the standard form $Ax + By = C$ . $\newline$ The equation $2x - 3y = -12$ is already in the correct form, but to match the standard form convention, we should write it as: $\newline$ $2x - 3y = -12$