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What is y=-(1)/(3)x-9 written in standard form? Choose 1 answer: (A) 3y=-x-27 (B) (1)/(3)x+y+9=0 (c) x+3y=-27 (D) y=-(1)/(3)(x+27)

What is y=−13x−9 y=-\frac{1}{3} x-9 written in standard form?\newlineChoose 11 answer:\newline(A) 3y=−x−27 3 y=-x-27 \newlineB 13x+y+9=0 \frac{1}{3} x+y+9=0 \newline(C) x+3y=−27 x+3 y=-27 \newline(D) y=−13(x+27) y=-\frac{1}{3}(x+27)

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Q. What is y=−13x−9 y=-\frac{1}{3} x-9 written in standard form?\newlineChoose 11 answer:\newline(A) 3y=−x−27 3 y=-x-27 \newlineB 13x+y+9=0 \frac{1}{3} x+y+9=0 \newline(C) x+3y=−27 x+3 y=-27 \newline(D) y=−13(x+27) y=-\frac{1}{3}(x+27)
  1. Multiply by ext{−3-3}: Multiply both sides of the equation by ext{−3-3} to eliminate the fraction.\newliney = ext{-} rac{11}{33}x - 99\newline ext{−3-3}y = x + 2727
  2. Move terms to one side: Move all terms to one side of the equation to get the standard form Ax+By=CAx + By = C.\newlinex+3y=−27x + 3y = -27

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