What is the slope of the line? x+3y=10 Choose 1 answer: (A) (1)/(10) (B) (1)/(3) (C) -(1)/(10) (D) -(1)/(3)

Isolating the term with y: We start by subtracting x from both sides of the equation to isolate the term with y. x + 3y - x = 10 - x This simplifies to: 3y = -x + 10Solving for y: Next, we divide each term by 3 to solve for y. (3y) / 3 = (-x) / 3 + 10 / 3 This simplifies to: y = -(1/3)x + 10/3Identifying the slope: Now that we have the equation in slope-intercept form, we can identify the slope. The coefficient of x is the slope of the line. In this case, the coefficient of x is -(1/3).Therefore, the slope of the line defined by the equation x + 3y = 10 is -(1/3).

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What is the slope of the line?

x+3y=10
Choose 1 answer:
(A)
(1)/(10)
(B)
(1)/(3)
(C)
-(1)/(10)
(D)
-(1)/(3)

What is the slope of the line? $\newline$ $x+3y=10$ $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{1}{10}$ $\newline$ (B) $\frac{1}{3}$ $\newline$ (C) $-\frac{1}{10}$ $\newline$ (D) $-\frac{1}{3}$

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Q. What is the slope of the line?

\newline

x+3y=10

\newline

Choose

1

answer:

\newline

(A)

\frac{1}{10}

\newline

(B)

\frac{1}{3}

\newline

(C)

-\frac{1}{10}

\newline

(D)

-\frac{1}{3}

Isolating the term with y: We start by subtracting $x$ from both sides of the equation to isolate the term with $y$ . $\newline$ $x + 3y - x = 10 - x$ $\newline$ This simplifies to: $\newline$ $3y = -x + 10$
Solving for y: Next, we divide each term by $3$ to solve for $y$ . $\newline$ $(3y) / 3 = (-x) / 3 + 10 / 3$ $\newline$ This simplifies to: $\newline$ $y = -(\frac{1}{3})x + \frac{10}{3}$
Identifying the slope: Now that we have the equation in slope-intercept form, we can identify the slope. The coefficient of $x$ is the slope of the line. In this case, the coefficient of $x$ is $-\left(\frac{1}{3}\right)$ .
Identifying the slope: Now that we have the equation in slope-intercept form, we can identify the slope. $\newline$ The coefficient of $x$ is the slope of the line. $\newline$ In this case, the coefficient of $x$ is $-\left(\frac{1}{3}\right)$ .Therefore, the slope of the line defined by the equation $x + 3y = 10$ is $-\left(\frac{1}{3}\right)$ .