What is the slope of a line that passes through the points (-1,(1)/(3)) and (0,-(1)/(3)) in the xy-plane? Choose 1 answer: (A) -(2)/(3) (B) -(1)/(3) (c) 0 (D) (2)/(3)

Find slope formula: To find the slope of the line, we use the slope formula, which is (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points the line passes through.Substitute given points: Substitute the given points into the slope formula. Let's take (-1, 1/3) as (x1, y1) and (0, -1/3) as (x2, y2). Slope = (y2 - y1) / (x2 - x1) = (-1/3 - 1/3) / (0 - (-1))Simplify numerator and denominator: Simplify the numerator and the denominator. Slope = (-1/3 - 1/3) / (0 + 1) = (-2/3) / 1Determine the slope: Since dividing by 1 does not change the value, the slope is -2/3. Slope = -2/3

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What is the slope of a line that passes through the points
(-1,(1)/(3)) and
(0,-(1)/(3)) in the
xy-plane?
Choose 1 answer:
(A)
-(2)/(3)
(B)
-(1)/(3)
(c) 0
(D)
(2)/(3)

What is the slope of a line that passes through the points $\left(-1, \frac{1}{3}\right)$ and $\left(0,-\frac{1}{3}\right)$ in the $x y$ -plane? $\newline$ Choose $1$ answer: $\newline$ (A) $-\frac{2}{3}$ $\newline$ (B) $-\frac{1}{3}$ $\newline$ (C) $0$ $\newline$ (D) $\frac{2}{3}$

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Math Problems

Algebra 1

Find a missing coordinate using slope

Full solution

Q. What is the slope of a line that passes through the points

\left(-1, \frac{1}{3}\right)

and

\left(0,-\frac{1}{3}\right)

in the

x y

-plane?

\newline

Choose

1

answer:

\newline

(A)

-\frac{2}{3}

\newline

(B)

-\frac{1}{3}

\newline

(C)

0

\newline

(D)

\frac{2}{3}

Find slope formula: To find the slope of the line, we use the slope formula, which is $(y_2 - y_1) / (x_2 - x_1)$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two points the line passes through.
Substitute given points: Substitute the given points into the slope formula. Let's take $(-1, \frac{1}{3})$ as $(x_1, y_1)$ and $(0, -\frac{1}{3})$ as $(x_2, y_2)$ . $\newline$ Slope = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{-\frac{1}{3} - \frac{1}{3}}{0 - (-1)}$
Simplify numerator and denominator: Simplify the numerator and the denominator. $\newline$ Slope = $\left(\frac{-1}{3} - \frac{1}{3}\right) / (0 + 1) = \frac{-2}{3} / 1$
Determine the slope: Since dividing by $1$ does not change the value, the slope is $-\frac{2}{3}$ . $\newline$ Slope = $-\frac{2}{3}$