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What is the period of the function 
g(x)=-sin(-8x-3)+5?
Give an exact value.
units

What is the period of the function g(x)=sin(8x3)+5? g(x)=-\sin (-8 x-3)+5 ? \newlineGive an exact value.\newlineunits

Full solution

Q. What is the period of the function g(x)=sin(8x3)+5? g(x)=-\sin (-8 x-3)+5 ? \newlineGive an exact value.\newlineunits
  1. Identify Function and Period: Identify the basic trigonometric function and its period.\newlineThe basic trigonometric function in g(x)g(x) is the sine function, sin(x)\sin(x), which has a period of 2π2\pi. The period of sin(Bx)\sin(Bx) is 2πB\frac{2\pi}{|B|}, where BB is the coefficient of xx.
  2. Determine Coefficient of xx: Determine the coefficient of xx in the argument of the sine function.\newlineIn the function g(x)=sin(8x3)g(x)=-\sin(-8x-3), the coefficient of xx is 8-8. We are interested in the absolute value of this coefficient to find the period.
  3. Calculate Period of g(x)g(x): Calculate the period of g(x)g(x). The period of g(x)g(x) is 2π2\pi divided by the absolute value of the coefficient of xx, which is 88. So, the period PP is given by P=2π8=2π8P = \frac{2\pi}{|8|} = \frac{2\pi}{8}.
  4. Simplify Period Expression: Simplify the expression for the period.\newlineSimplifying 2π8\frac{2\pi}{8} gives us π4\frac{\pi}{4}. Therefore, the period of the function g(x)g(x) is π4\frac{\pi}{4}.

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