What is the period of the function f(x)=-6sin(3pi x+4)-2? Give an exact value. units

Sine Function Period Determination: The period of a sine function is determined by the coefficient of x within the sine function. The general form of a sine function is f(x) = A sin(Bx + C) + D, where the period is given by 2π/B. In the given function f(x) = -6sin(3πx + 4) - 2, the coefficient of x is 3π.Identifying Coefficient of x: To find the period of the function, we use the formula for the period of a sine function, which is 2π divided by the coefficient of x. In this case, the coefficient is 3π. So, the period T is T = 2π / (3π).Calculating Period Formula: We simplify the expression for the period by dividing 2π by 3π. T = 2π / (3π) = 2/3.Simplifying Period Expression: The period of the function is 2/3, which is the exact value.

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What is the period of the function
f(x)=-6sin(3pi x+4)-2?
Give an exact value.
units

What is the period of the function $f(x)=-6 \sin (3 \pi x+4)-2$ ? $\newline$ Give an exact value. $\newline$ units

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Q. What is the period of the function

f(x)=-6 \sin (3 \pi x+4)-2

\newline

Give an exact value.

\newline

units

Sine Function Period Determination: The period of a sine function is determined by the coefficient of $x$ within the sine function. The general form of a sine function is $f(x) = A \sin(Bx + C) + D$ , where the period is given by $\frac{2\pi}{B}$ . $\newline$ In the given function $f(x) = -6\sin(3\pi x + 4) - 2$ , the coefficient of $x$ is $3\pi$ .
Identifying Coefficient of x: To find the period of the function, we use the formula for the period of a sine function, which is $2\pi$ divided by the coefficient of $x$ . In this case, the coefficient is $3\pi$ . So, the period $T$ is $T = \frac{2\pi}{3\pi}$ .
Calculating Period Formula: We simplify the expression for the period by dividing $2\pi$ by $3\pi$ . $T = \frac{2\pi}{3\pi} = \frac{2}{3}$ .
Simplifying Period Expression: The period of the function is $\frac{2}{3}$ , which is the exact value.