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What is the missing constant term in the perfect square that starts with 
x^(2)+10 x ?

What is the missing constant term in the perfect square that starts with x2+10xx^{2}+10x ?

Full solution

Q. What is the missing constant term in the perfect square that starts with x2+10xx^{2}+10x ?
  1. Finding the Perfect Square Trinomial: To complete the square for an expression of the form x2+bxx^2 + bx, we need to find a number that can be added to make it a perfect square trinomial. The formula for the constant term in a perfect square trinomial is (b2)2(\frac{b}{2})^2.
  2. Calculating the Constant Term: In the given expression x2+10xx^2 + 10x, the coefficient bb in front of xx is 1010. To find the constant term, we need to divide bb by 22 and then square the result.
  3. Squaring the Result: Divide 1010 by 22 to get 55. Then square 55 to find the constant term.\newlineCalculation: (102)2=52=25(\frac{10}{2})^2 = 5^2 = 25.
  4. Completing the Perfect Square Trinomial: The missing constant term that would make x2+10xx^2 + 10x a perfect square is 2525. Adding this term to the expression gives us (x+5)2(x + 5)^2, which is the perfect square trinomial.

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