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What is the missing constant term in the perfect square that starts with
x^(2)-16 x ?

What is the missing constant term in the perfect square that starts with $x^{2}-16x$ ?

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Solve a quadratic equation by completing the square

Full solution

Q. What is the missing constant term in the perfect square that starts with

x^{2}-16x

?

Step $1$ : Identify the expression: To complete the square for an expression of the form $x^2 + bx$ , we need to find the value that makes it a perfect square trinomial. The formula to find the constant term is $\left(\frac{b}{2}\right)^2$ .
Step $2$ : Determine the coefficient: In the given expression $x^2 - 16x$ , the coefficient $b$ is $-16$ . We need to find igg(rac{-16}{2}igg)^2.
Step $3$ : Calculate the constant term: Divide $-16$ by $2$ to get $-8$ . Then square $-8$ to find the constant term. $\newline$ $\left(\frac{-16}{2}\right)^2 = (-8)^2 = 64$
Step $4$ : Complete the square: The missing constant term that completes the square for the expression $x^2 - 16x$ is $64$ .

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