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What is the missing constant term in the perfect square that starts with 
x^(2)+2x ?

What is the missing constant term in the perfect square that starts with x2+2xx^{2}+2x ?

Full solution

Q. What is the missing constant term in the perfect square that starts with x2+2xx^{2}+2x ?
  1. Identify Trinomial Form: To form a perfect square trinomial starting with x2+2xx^2 + 2x, we need to find a constant term (c)(c) such that the trinomial can be expressed as (x+b)2(x + b)^2, where the linear coefficient (2b)(2b) is equal to 2x2x.
  2. Find Linear Coefficient: The linear coefficient in the expression x2+2xx^2 + 2x is 22. To find the constant term, we use the relationship 2b=22b = 2, which implies that b=1b = 1.
  3. Calculate Constant Term: Knowing that b=1b = 1, we can find the constant term by squaring bb. The constant term cc will be b2b^2, which is 121^2.
  4. Finalize Perfect Square Trinomial: Calculating the square of bb gives us c=12=1c = 1^2 = 1.

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