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Wang Lei would like to build a 
144ft^(2) rectangular garden. He plans to enclose this area with exactly 
50ft of fencing. Which of the following equations could be used to find the width, 
x, of Wang Lei's garden?
Choose 1 answer:
(A) 
x(72-x)=50
(B) 
x(25-x)=144
(C) 
x(144-2x)=50
(D) 
x(50-2x)=144

Wang Lei would like to build a 144ft2 144 \mathrm{ft}^{2} rectangular garden. He plans to enclose this area with exactly 50ft 50 \mathrm{ft} of fencing. Which of the following equations could be used to find the width, x x , of Wang Lei's garden?\newlineChoose 11 answer:\newline(A) x(72x)=50 x(72-x)=50 \newline(B) x(25x)=144 x(25-x)=144 \newline(C) x(1442x)=50 x(144-2 x)=50 \newline(D) x(502x)=144 x(50-2 x)=144

Full solution

Q. Wang Lei would like to build a 144ft2 144 \mathrm{ft}^{2} rectangular garden. He plans to enclose this area with exactly 50ft 50 \mathrm{ft} of fencing. Which of the following equations could be used to find the width, x x , of Wang Lei's garden?\newlineChoose 11 answer:\newline(A) x(72x)=50 x(72-x)=50 \newline(B) x(25x)=144 x(25-x)=144 \newline(C) x(1442x)=50 x(144-2 x)=50 \newline(D) x(502x)=144 x(50-2 x)=144
  1. Understanding the Rectangle Area: Understand the relationship between the area of a rectangle and its sides.\newlineThe area of a rectangle is given by the product of its length and width. Wang Lei's garden has an area of 144144 square feet. If we denote the width as xx and the length as yy, then the area can be represented as x×y=144x \times y = 144.
  2. Relating Perimeter to Fencing: Relate the perimeter of the rectangle to the fencing. The perimeter of a rectangle is given by 22 times the sum of its length and width. Wang Lei has 5050 feet of fencing, which means the perimeter of the garden is 5050 feet. This can be represented as 2x+2y=502x + 2y = 50.
  3. Solving for a Variable: Solve the perimeter equation for one of the variables.\newlineTo find an equation involving only xx, we can solve the perimeter equation for yy. Dividing the entire equation by 22 gives us x+y=25x + y = 25. Now, solve for yy: y=25xy = 25 - x.
  4. Substituting into the Area Equation: Substitute the expression for yy into the area equation.\newlineNow that we have yy in terms of xx, we can substitute it into the area equation: x×(25x)=144x \times (25 - x) = 144. This equation relates the width xx to the area of the garden.
  5. Matching the Derived Equation: Check the given options to see which one matches the derived equation.\newlineComparing the derived equation x(25x)=144x(25 - x) = 144 with the given options, we see that option (B) matches the equation we found.

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