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V=(s^(2)h)/(3)
The formula gives the volume of a right square pyramid of height 
h and square base of side length 
s. If the side length of a right square pyramid increases by 
30% while the height remains constant, what happens to the volume?
Choose 1 answer:
(A) The volume increases by 
30%.
(B) The volume increases by 
69%.
(C) The volume increases by 
169%.
(D) The volume increases by 
300%.

V=s2h3 V=\frac{s^{2} h}{3} \newlineThe formula gives the volume of a right square pyramid of height h h and square base of side length s s . If the side length of a right square pyramid increases by 30% 30 \% while the height remains constant, what happens to the volume?\newlineChoose 11 answer:\newline(A) The volume increases by 30% 30 \% .\newline(B) The volume increases by 69% 69 \% .\newline(C) The volume increases by 169% 169 \% .\newline(D) The volume increases by 300% 300 \% .

Full solution

Q. V=s2h3 V=\frac{s^{2} h}{3} \newlineThe formula gives the volume of a right square pyramid of height h h and square base of side length s s . If the side length of a right square pyramid increases by 30% 30 \% while the height remains constant, what happens to the volume?\newlineChoose 11 answer:\newline(A) The volume increases by 30% 30 \% .\newline(B) The volume increases by 69% 69 \% .\newline(C) The volume increases by 169% 169 \% .\newline(D) The volume increases by 300% 300 \% .
  1. Denoting original side length: Let's denote the original side length of the square base as ss and the height of the pyramid as hh. The original volume VV of the pyramid is given by the formula V=s2h3V = \frac{s^2 \cdot h}{3}. Now, if the side length increases by 30%30\%, the new side length ss' will be s=s+0.30s=1.30ss' = s + 0.30s = 1.30s. We need to calculate the new volume VV' with the increased side length and compare it to the original volume VV to find the percentage increase.
  2. Calculating new side length: Using the formula for the volume of the pyramid with the new side length ss', the new volume VV' is V=(1.30s)2×h3V' = \frac{(1.30s)^2 \times h}{3}. We need to square the new side length (1.30s)2(1.30s)^2 to find the factor by which the volume increases.
  3. Calculating new volume: Calculating the square of the new side length gives us (1.30s)2=(1.30)2×s2=1.69×s2(1.30s)^2 = (1.30)^2 \times s^2 = 1.69 \times s^2. This shows that the area of the base, and thus the volume, increases by a factor of 1.691.69 when the side length increases by 30%30\%.
  4. Expressing new volume in terms of original volume: Now we can express the new volume VV' in terms of the original volume VV. Since V=s2h3V = \frac{s^2 \cdot h}{3}, the new volume VV' will be V=1.69s2h3=1.69VV' = \frac{1.69 \cdot s^2 \cdot h}{3} = 1.69V. This means the new volume is 1.691.69 times the original volume.
  5. Calculating percentage increase in volume: To find the percentage increase in volume, we subtract the original volume from the new volume and then divide by the original volume: Percentage increase = ((VV)/V)×100%((V' - V) / V) \times 100\%. Substituting V=1.69VV' = 1.69V and VV, we get Percentage increase = ((1.69VV)/V)×100%=(0.69V/V)×100%=69%((1.69V - V) / V) \times 100\% = (0.69V / V) \times 100\% = 69\%.
  6. Conclusion: Therefore, the volume of the pyramid increases by 69%69\% when the side length increases by 30%30\% while the height remains constant. This corresponds to answer choice (B)(B).

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