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Today, the population of Canyon Falls is 22,500 and the population of Swift Creek is 15,200 . The population of Canyon Falls is decreasing at the rate of 740 people each year while the population of Swift Creek is increasing at the rate of 1,500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?
Choose 1 answer:
9 years
(B) 
10 years
(c) 11 years
(D) 12 years

Today, the population of Canyon Falls is 2222,500500 and the population of Swift Creek is 1515,200200 . The population of Canyon Falls is decreasing at the rate of 740740 people each year while the population of Swift Creek is increasing at the rate of 11,500500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?\newlineChoose 11 answer:\newline(A) 99 years\newline(B) 10 10 years\newline(C) 1111 years\newline(D) 1212 years

Full solution

Q. Today, the population of Canyon Falls is 2222,500500 and the population of Swift Creek is 1515,200200 . The population of Canyon Falls is decreasing at the rate of 740740 people each year while the population of Swift Creek is increasing at the rate of 11,500500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?\newlineChoose 11 answer:\newline(A) 99 years\newline(B) 10 10 years\newline(C) 1111 years\newline(D) 1212 years
  1. Question prompt: Question prompt: In how many years from today will the population of Swift Creek equal twice the population of Canyon Falls, given their respective annual population change rates?
  2. Equation setup: Let's denote the number of years from today as yy. We need to set up an equation that represents the situation where the population of Swift Creek equals twice the population of Canyon Falls after yy years.
  3. Population of Canyon Falls: The population of Canyon Falls after yy years will be 22,500740y22,500 - 740y, since it decreases by 740740 people each year.
  4. Population of Swift Creek: The population of Swift Creek after yy years will be 15,200+1,500y15,200 + 1,500y, since it increases by 1,5001,500 people each year.
  5. Equation solution: We want the population of Swift Creek to be twice the population of Canyon Falls. So, we set up the equation: 15,200+1,500y=2×(22,500740y)15,200 + 1,500y = 2 \times (22,500 - 740y).
  6. Solving for y: Now, we solve for "y". First, distribute the 22 on the right side of the equation: 15,200+1,500y=45,0001,480y15,200 + 1,500y = 45,000 - 1,480y.
  7. Final answer: Next, we combine like terms by adding 1,480y1,480y to both sides and subtracting 15,20015,200 from both sides: 1,500y+1,480y=45,00015,2001,500y + 1,480y = 45,000 - 15,200.
  8. Final answer: Next, we combine like terms by adding 1,480y1,480y to both sides and subtracting 15,20015,200 from both sides: 1,500y+1,480y=45,00015,2001,500y + 1,480y = 45,000 - 15,200. This simplifies to 2,980y=29,8002,980y = 29,800. Now, we divide both sides by 2,9802,980 to solve for yy: y=29,800/2,980y = 29,800 / 2,980.
  9. Final answer: Next, we combine like terms by adding 1,480y1,480y to both sides and subtracting 15,20015,200 from both sides: 1,500y+1,480y=45,00015,2001,500y + 1,480y = 45,000 - 15,200. This simplifies to 2,980y=29,8002,980y = 29,800. Now, we divide both sides by 2,9802,980 to solve for yy: y=29,800/2,980y = 29,800 / 2,980. Performing the division gives us y=10y = 10. Therefore, it will take 1010 years for the population of Swift Creek to equal twice the population of Canyon Falls.

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