Q. The sum of the first 6 terms of a geometric series is 15,624 and the common ratio is 5 .What is the first term of the series?
Formula Application: The sum of the first n terms of a geometric series can be found using the formula Sn=(1−r)a(1−rn), where Sn is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms. We are given that S6=15,624, r=5, and n=6. We need to solve for a.
Plug Known Values: First, let's plug the known values into the formula for the sum of a geometric series:S6=a(1−56)/(1−5)15,624=a(1−15625)/(1−5)
Simplify Equation: Now, let's simplify the denominator and the numerator inside the parentheses:15,624=a(1−15625)/(−4)15,624=a(−15624)/(−4)
Divide by Constant: Next, we simplify the right side of the equation by dividing −15624 by −4:15,624=a(3906)
Final Division: To find the value of a, we divide both sides of the equation by 3906:a=390615,624
Find Value of a: Now, we perform the division to find the value of a:a=4
More problems from Find the sum of a finite geometric series