The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled byP(x)=−15x(x−8)What is the maximum power possible?watts
Q. The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled byP(x)=−15x(x−8)What is the maximum power possible?watts
Analyzing Quadratic Function: To find the maximum power possible, we need to analyze the quadratic function P(x)=−15x(x−8). This is a parabola that opens downwards because the coefficient of x2 is negative (−15). The maximum value of this function occurs at the vertex of the parabola.
Finding Vertex: The vertex of a parabola given by the function f(x)=ax2+bx+c is at the point (h,k), where h=−2ab. In our case, the function P(x)=−15x2+120x can be written in the form ax2+bx+c by expanding the given expression.
Expanding Function: Expanding P(x)=−15x(x−8) gives us P(x)=−15x2+120x. Here, a=−15 and b=120. There is no c term, so c=0.
Calculating x-coordinate: Using the formula for the vertex h=−2ab, we substitute a=−15 and b=120 to find the x-coordinate of the vertex.h=−2⋅−15120=−−30120=4.
Substitute x into Function: The x-coordinate of the vertex is 4. To find the y-coordinate, which is the maximum power, we substitute x=4 back into the function P(x).P(4)=−15×4×(4−8).
Calculate Maximum Power: Calculate P(4)=−15×4×(4−8)=−15×4×−4=−15×16=−240.
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