The perimeter of a rectangular movie screen at a local cinema is 148 feet. If the length of the screen is 30 feet longer than the width, what is the length of the screen, in feet?

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Denoting the width: Let's denote the width of the screen as $ w $ feet. According to the problem, the length of the screen is 30 feet longer than the width, so we can express the length as $ w + 30 $ feet.Calculating the perimeter: The perimeter of a rectangle is calculated by the formula $ P = 2l + 2w $, where $ P $ is the perimeter, $ l $ is the length, and $ w $ is the width. We know the perimeter is 148 feet, so we can set up the equation $ 148 = 2(w + 30) + 2w $.Simplifying the equation: Now let's simplify the equation: $ 148 = 2w + 60 + 2w $.Combining like terms: Combine like terms: $ 148 = 4w + 60 $.Isolating the term with w: Subtract 60 from both sides to isolate the term with $ w $: $ 148 - 60 = 4w $.Performing the subtraction: Perform the subtraction: $ 88 = 4w $.Solving for w: Divide both sides by 4 to solve for $ w $: $ w = 88 / 4 $.Calculating the width: Calculate the value of $ w $: $ w = 22 $ feet.Finding the length: Now that we have the width, we can find the length by adding 30 to the width: $ l = w + 30 = 22 + 30 $.Calculating the length: Calculate the length: $ l = 52 $ feet.

The perimeter of a rectangular movie screen at a local cinema is $148$ feet. If the length of the screen is $30$ feet longer than the width, what is the length of the screen, in feet?

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The perimeter of a rectangular movie screen at a local cinema is 148148148 feet. If the length of the screen is 303030 feet longer than the width, what is the length of the screen, in feet?

The perimeter of a rectangular movie screen at a local cinema is $148$ feet. If the length of the screen is $30$ feet longer than the width, what is the length of the screen, in feet?