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The number of problems assigned as homework by a savvy math professor is a function of the length of the class on a particular day, which is either 45 minutes, 90 minutes, or 135 minutes. He first multiplies the number of minutes by 4 and then divides that number by 9 . Finally, he subtracts 12 from that amount. Which of the following functions best represents the number of math problems the professor assigns depending on the length of the class, 
t, in minutes?
Choose 1 answer:
(A) 
f(t)=(4)/(9)t-12
(B) 
f(t)=(4)/(9)(t-12)
(c) 
f(t)=12-(4)/(9)t
(D) 
f(t)=12+(4)/(9)t

The number of problems assigned as homework by a savvy math professor is a function of the length of the class on a particular day, which is either 4545 minutes, 9090 minutes, or 135135 minutes. He first multiplies the number of minutes by 44 and then divides that number by 99 . Finally, he subtracts 1212 from that amount. Which of the following functions best represents the number of math problems the professor assigns depending on the length of the class, t t , in minutes?\newlineChoose 11 answer:\newline(A) f(t)=49t12 f(t)=\frac{4}{9} t-12 \newline(B) f(t)=49(t12) f(t)=\frac{4}{9}(t-12) \newline(C) f(t)=1249t f(t)=12-\frac{4}{9} t \newline(D) f(t)=12+49t f(t)=12+\frac{4}{9} t

Full solution

Q. The number of problems assigned as homework by a savvy math professor is a function of the length of the class on a particular day, which is either 4545 minutes, 9090 minutes, or 135135 minutes. He first multiplies the number of minutes by 44 and then divides that number by 99 . Finally, he subtracts 1212 from that amount. Which of the following functions best represents the number of math problems the professor assigns depending on the length of the class, t t , in minutes?\newlineChoose 11 answer:\newline(A) f(t)=49t12 f(t)=\frac{4}{9} t-12 \newline(B) f(t)=49(t12) f(t)=\frac{4}{9}(t-12) \newline(C) f(t)=1249t f(t)=12-\frac{4}{9} t \newline(D) f(t)=12+49t f(t)=12+\frac{4}{9} t
  1. Problem Understanding: Understand the problem.\newlineThe professor's method for determining the number of problems is to multiply the class length in minutes by 44, divide by 99, and then subtract 1212. We need to translate this process into a function of tt, where tt represents the class length in minutes.
  2. Mathematical Function Translation: Translate the professor's method into a mathematical function.\newlineFirst, he multiplies the number of minutes tt by 44, which gives us 4t4t.\newlineThen, he divides that number by 99, which can be represented as 4t9\frac{4t}{9} or (49)t\left(\frac{4}{9}\right)t.\newlineFinally, he subtracts 1212 from that amount, which gives us the function f(t)=(49)t12f(t) = \left(\frac{4}{9}\right)t - 12.
  3. Matching Function with Choices: Match the function with the given choices.\newlineThe function we derived from the professor's method is f(t)=49t12f(t) = \frac{4}{9}t - 12. Now we need to find which choice matches this function.\newline(A) f(t)=49t12f(t) = \frac{4}{9}t - 12\newline(B) f(t)=49(t12)f(t) = \frac{4}{9}(t - 12)\newline(C) f(t)=1249tf(t) = 12 - \frac{4}{9}t\newline(D) f(t)=12+49tf(t) = 12 + \frac{4}{9}t
  4. Choosing the Correct Function: Choose the correct function.\newlineBy comparing the function we derived with the choices, we can see that choice (A) f(t)=49t12f(t) = \frac{4}{9}t - 12 is the correct representation of the professor's method for assigning homework problems.

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