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The graph of a sinusoidal function intersects its midline at 
(0,2) and then has a minimum point at 
(3,-6).
Write the formula of the function, where 
x is entered in radians.

The graph of a sinusoidal function intersects its midline at (0,2) (0,2) and then has a minimum point at (3,6) (3,-6) .\newlineWrite the formula of the function, where x x is entered in radians.\newlinef(x)= f(x)=\square

Full solution

Q. The graph of a sinusoidal function intersects its midline at (0,2) (0,2) and then has a minimum point at (3,6) (3,-6) .\newlineWrite the formula of the function, where x x is entered in radians.\newlinef(x)= f(x)=\square
  1. Identify Amplitude, Midline, and Phase Shift: Identify the amplitude, midline, and phase shift of the sinusoidal function.\newlineThe midline of the function is the horizontal line that the function oscillates around. Given the point (0,2)(0,2), we know that the midline is y=2y = 2. The minimum point of the function is (3,6)(3,-6). Since the midline is y=2y = 2 and the minimum value is 6-6, the amplitude of the function is the distance from the midline to the minimum, which is 2(6)=82 - (-6) = 8. The function has a minimum at x=3x = 3, which means the phase shift is 33 units to the right.
  2. Determine Period: Determine the period of the sinusoidal function.\newlineSince no information about the period is given, we assume the function has the same period as the basic sine function, which is 2π2\pi. Therefore, the period of the function is 2π2\pi.
  3. Write General Form: Write the general form of the sinusoidal function.\newlineThe general form of a sinusoidal function is y=Asin(B(xC))+Dy = A \cdot \sin(B(x - C)) + D, where AA is the amplitude, BB is related to the period by the formula B=2πperiodB = \frac{2\pi}{\text{period}}, CC is the phase shift, and DD is the vertical shift (midline). We have already determined that A=8A = 8, B=1B = 1 (since the period is 2π2\pi), C=3C = 3, and AA00.
  4. Substitute Known Values: Substitute the known values into the general form of the sinusoidal function.\newlineUsing the values A=8A = 8, B=1B = 1, C=3C = 3, and D=2D = 2, we substitute into the general form to get y=8sin(x3)+2y = 8 \cdot \sin(x - 3) + 2. However, since the function has a minimum at x=3x = 3, we need to use the cosine function, which starts at a maximum, and include a negative sign to reflect the graph vertically. This gives us y=8cos(x3)+2y = -8 \cdot \cos(x - 3) + 2.

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