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The graph of a line in the 
xy-plane has a slope of 4 and contains the point 
(1,-5). The graph of a second line passes through the points 
(0,4) and 
(12,0). If the two lines intersect at the point 
(a,b), what is the value of 
a-b ?
Choose 1 answer:
(A) -9
(B) -5
(c) 0
(D) 4

The graph of a line in the xy x y -plane has a slope of 44 and contains the point (1,5) (1,-5) . The graph of a second line passes through the points (0,4) (0,4) and (12,0) (12,0) . If the two lines intersect at the point (a,b) (a, b) , what is the value of ab a-b ?\newlineChoose 11 answer:\newline(A) 9-9\newline(B) 5-5\newline(C) 00\newline(D) 44

Full solution

Q. The graph of a line in the xy x y -plane has a slope of 44 and contains the point (1,5) (1,-5) . The graph of a second line passes through the points (0,4) (0,4) and (12,0) (12,0) . If the two lines intersect at the point (a,b) (a, b) , what is the value of ab a-b ?\newlineChoose 11 answer:\newline(A) 9-9\newline(B) 5-5\newline(C) 00\newline(D) 44
  1. Find First Line Equation: First, let's find the equation of the first line with a slope of 44 that contains the point (1,5)(1, -5). Using the point-slope form of a line equation: \newlineyy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is the point on the line. \newliney(5)=4(x1)y - (-5) = 4(x - 1)
  2. Simplify First Line Equation: Simplify the equation of the first line:\newliney+5=4x4y + 5 = 4x - 4\newliney=4x45y = 4x - 4 - 5\newliney=4x9y = 4x - 9\newlineThis is the equation of the first line.
  3. Find Second Line Equation: Now, let's find the equation of the second line that passes through the points (0,4)(0, 4) and (12,0)(12, 0). We can use the slope formula: \newlinem=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} \newlinem=04120m = \frac{0 - 4}{12 - 0} \newlinem=412m = \frac{-4}{12} \newlinem=13m = -\frac{1}{3}
  4. Calculate Intersection Point Slope: Using the point-slope form again for the second line with the point (0,4)(0, 4):\newliney4=(13)(x0)y - 4 = \left(-\frac{1}{3}\right)(x - 0)\newliney4=(13)xy - 4 = \left(-\frac{1}{3}\right)x\newliney=(13)x+4y = \left(-\frac{1}{3}\right)x + 4\newlineThis is the equation of the second line.
  5. Find Intersection Point: To find the intersection point (a,b)(a, b), we set the equations of the two lines equal to each other:\newline4x9=(13)x+44x - 9 = (-\frac{1}{3})x + 4
  6. Calculate x-coordinate: Solve for xx: \newline4x+(13)x=4+94x + (\frac{1}{3})x = 4 + 9\newline(123)x+(13)x=13(\frac{12}{3})x + (\frac{1}{3})x = 13 \newline(133)x=13(\frac{13}{3})x = 13 \newlinex=13(133)x = \frac{13}{(\frac{13}{3})} \newlinex=13×(313)x = 13 \times (\frac{3}{13}) \newlinex=3x = 3
  7. Calculate y-coordinate: Now that we have the x-coordinate of the intersection point, we can find the y-coordinate by plugging x=3x = 3 into one of the line equations. Let's use the first line's equation:\newliney=4x9y = 4x - 9\newliney=4(3)9y = 4(3) - 9\newliney=129y = 12 - 9\newliney=3y = 3
  8. Determine Intersection Point: We have found the intersection point (a,b)(a, b) to be (3,3)(3, 3). Now we can find aba - b: \newlineab=33a - b = 3 - 3 \newlineab=0a - b = 0

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