Q. The common ratio of a geometric series is 41 and the sum of the first 4 terms is 170 .What is the first term of the series?
Geometric series sum formula: The sum of the first n terms of a geometric series is given by the formula:Sn=1−ra1(1−rn)where Sn is the sum of the first n terms, a1 is the first term, r is the common ratio, and n is the number of terms.
Given values: We are given the sum of the first 4 terms S4 is 170, the common ratio r is 41, and we need to find the first term a1.
Substitute values into formula: Substitute the given values into the sum formula:170=1−41a1(1−(41)4)
Simplify the equation: Simplify the equation: 170=(a1(1−2561))/(43)
Isolate the term involving a1: Multiply both sides by (43) to isolate the term involving a1:170×(43)=a1(1−2561)
Calculate left side of the equation: Calculate the left side of the equation: $\(170\) \times \left(\frac{\(3\)}{\(4\)}\right) = \(127\).\(5\)
Equation with simplified right side: Now we have: \(127.5 = a_1(1 - \frac{1}{256})\)
Divide both sides to solve for \(a_1\): Simplify the right side of the equation: \(127.5 = a_1\left(\frac{255}{256}\right)\)
Calculate the value of \(a_1\): Divide both sides by \((255/256)\) to solve for \(a_1\):\(\newline\)\[a_1 = \frac{127.5}{(255/256)}\]
Perform the multiplication: Calculate the value of \(a_1\): \(\newline\)\[a_1 = 127.5 \times \left(\frac{256}{255}\right)\]
Perform the multiplication: Calculate the value of \(a_1\): \(\newline\)\[a_1 = 127.5 \times \left(\frac{256}{255}\right)\]Perform the multiplication: \(\newline\)\[a_1 = 128\]
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