Solve the system of equations. {:[-7x-6y=4],[x=-3y+8],[x=◻],[y=◻]:}

Substitute x in first equation: First, let's substitute the value of x from the second equation into the first equation. So, we replace x in the first equation with -3y + 8. -7(-3y + 8) - 6y = 4Distribute -7: Now, let's distribute -7 into the parentheses. 21y - 56 - 6y = 4Combine like terms: Combine like terms. 15y - 56 = 4Add 56 to isolate y: Add 56 to both sides to isolate the y term. 15y = 60Divide by 15 for y: Divide both sides by 15 to solve for y. y = 4Substitute y back for x: Now, substitute the value of y back into one of the original equations to solve for x. We'll use the second equation: x = -3y + 8. x = -3(4) + 8Calculate x value: Calculate the value of x. x = -12 + 8Simplify x value: Simplify to find the value of x. x = -4

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Solve the system of equations.

{:[-7x-6y=4],[x=-3y+8],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -7 x-6 y=4 \\ x=-3 y+8 \\ x=\square \\ y=\square \end{array}$

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Algebra 1

Solve a system of equations using substitution

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Q. Solve the system of equations.

\newline

\begin{array}{l} -7 x-6 y=4 \\ x=-3 y+8 \\ x=\square \\ y=\square \end{array}

Substitute $x$ in first equation: First, let's substitute the value of $x$ from the second equation into the first equation. So, we replace $x$ in the first equation with $-3y + 8$ . $\newline$ $-7(-3y + 8) - 6y = 4$
Distribute $-7$ : Now, let's distribute $-7$ into the parentheses. $21y - 56 - 6y = 4$
Combine like terms: Combine like terms. $15y - 56 = 4$
Add $56$ to isolate $y$ : Add $56$ to both sides to isolate the $y$ term. $15y = 60$
Divide by $15$ for $y$ : Divide both sides by $15$ to solve for $y$ . $y = 4$
Substitute $y$ back for $x$ : Now, substitute the value of $y$ back into one of the original equations to solve for $x$ . We'll use the second equation: $x = -3y + 8$ . $\newline$ $x = -3(4) + 8$
Calculate x value: Calculate the value of $x$ . $x = -12 + 8$
Simplify $x$ value: Simplify to find the value of $x$ . $x = -4$