Solve the system of equations. {:[6x-5y=15],[x=y+3],[x=◻],[y=◻]:}

Solve second equation for x: Solve the second equation for x. The second equation is x = y + 3. We can use this to substitute for x in the first equation.Substitute x into first equation: Substitute x = y + 3 into the first equation. The first equation is 6x - 5y = 15. Replace x with y + 3 to get 6(y + 3) - 5y = 15.Distribute and combine like terms: Distribute and combine like terms. 6(y + 3) - 5y = 15 becomes 6y + 18 - 5y = 15. This simplifies to y + 18 = 15.Solve for y: Solve for y. Subtract 18 from both sides to isolate y. y + 18 - 18 = 15 - 18, which simplifies to y = -3.Substitute y into second equation: Substitute y = -3 back into the second equation to find x. The second equation is x = y + 3. Replace y with -3 to get x = -3 + 3.Solve for x: Solve for x. x = -3 + 3 simplifies to x = 0.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve the system of equations.

{:[6x-5y=15],[x=y+3],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} 6 x-5 y=15 \\ x=y+3 \\ x=\square \\ y=\square \end{array}$

View step-by-step help

Home

Math Problems

Algebra 1

Solve a system of equations using substitution

Full solution

Q. Solve the system of equations.

\newline

\begin{array}{l} 6 x-5 y=15 \\ x=y+3 \\ x=\square \\ y=\square \end{array}

Solve second equation for x: Solve the second equation for x. $\newline$ The second equation is $x = y + 3$ . We can use this to substitute for $x$ in the first equation.
Substitute $x$ into first equation: Substitute $x = y + 3$ into the first equation. $\newline$ The first equation is $6x - 5y = 15$ . Replace $x$ with $y + 3$ to get $6(y + 3) - 5y = 15$ .
Distribute and combine like terms: Distribute and combine like terms. $\newline$ $6(y + 3) - 5y = 15$ becomes $6y + 18 - 5y = 15$ . $\newline$ This simplifies to $y + 18 = 15$ .
Solve for y: Solve for y. $\newline$ Subtract $18$ from both sides to isolate $y$ . $\newline$ $y + 18 - 18 = 15 - 18$ , which simplifies to $y = -3$ .
Substitute $y$ into second equation: Substitute $y = -3$ back into the second equation to find $x$ . $\newline$ The second equation is $x = y + 3$ . Replace $y$ with $-3$ to get $x = -3 + 3$ .
Solve for x: Solve for x. $x = -3 + 3$ simplifies to $x = 0$ .