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Solve the system of equations.

{:[5x-7y=58],[y=-x+2],[x=◻],[y=◻]:}

Solve the system of equations.\newline5x7y=58y=x+2x=y= \begin{array}{l} 5 x-7 y=58 \\ y=-x+2 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline5x7y=58y=x+2x=y= \begin{array}{l} 5 x-7 y=58 \\ y=-x+2 \\ x=\square \\ y=\square \end{array}
  1. Substitute yy into first equation: Substitute yy from the second equation into the first equation.\newlineWe have y=x+2y = -x + 2. Substitute this into 5x7y=585x - 7y = 58.\newline5x7(x+2)=585x - 7(-x + 2) = 58
  2. Distribute and simplify: Distribute the 7-7 across the terms in the parentheses and simplify.5x+7x14=585x + 7x - 14 = 5812x14=5812x - 14 = 58
  3. Isolate the term with x: Add 1414 to both sides to isolate the term with the variable x.\newline1212x - 1414 + 1414 = 5858 + 1414\newline1212x = 7272
  4. Solve for x: Divide both sides by 1212 to solve for x.\newline12x12=7212\frac{12x}{12} = \frac{72}{12}\newlinex=6x = 6
  5. Substitute xx back into second equation: Substitute xx back into the second equation to solve for yy.
    y=x+2y = -x + 2
    y=6+2y = -6 + 2
    y=4y = -4
  6. Write the solution as an ordered pair: Write the solution as an ordered pair.\newlineThe solution is (x,y)=(6,4)(x, y) = (6, -4).

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