Solve the system of equations. {:[3x+4y=-23],[x=3y+1],[x=◻],[y=◻]:}

Identify Equations: Identify the given system of equations. We have the following system of equations: 3x + 4y = -23 x = 3y + 1Substitute and Solve: Substitute the second equation into the first equation. Since x = 3y + 1, we can replace x in the first equation with 3y + 1 to solve for y. 3(3y + 1) + 4y = -23Combine Terms: Distribute and combine like terms. 9y + 3 + 4y = -23 13y + 3 = -23Isolate Variable: Isolate the variable y. Subtract 3 from both sides of the equation to solve for y. 13y = -23 - 3 13y = -26Find Value of y: Divide both sides by 13 to find the value of y. y = -26 / 13 y = -2Substitute for x: Substitute the value of y back into the second equation to solve for x. x = 3(-2) + 1Calculate x: Calculate the value of x. x = -6 + 1 x = -5

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Solve the system of equations.

{:[3x+4y=-23],[x=3y+1],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} 3 x+4 y=-23 \\ x=3 y+1 \\ x=\square \\ y=\square \end{array}$

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Algebra 1

Solve a system of equations using substitution

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Q. Solve the system of equations.

\newline

\begin{array}{l} 3 x+4 y=-23 \\ x=3 y+1 \\ x=\square \\ y=\square \end{array}

Identify Equations: Identify the given system of equations. $\newline$ We have the following system of equations: $\newline$ $3x + 4y = -23$ $\newline$ $x = 3y + 1$
Substitute and Solve: Substitute the second equation into the first equation. $\newline$ Since $x = 3y + 1$ , we can replace $x$ in the first equation with $3y + 1$ to solve for $y$ . $\newline$ $3(3y + 1) + 4y = -23$
Combine Terms: Distribute and combine like terms. $\newline$ $9y + 3 + 4y = -23$ $\newline$ $13y + 3 = -23$
Isolate Variable: Isolate the variable $y$ . $\newline$ Subtract $3$ from both sides of the equation to solve for $y$ . $\newline$ $13y = -23 - 3$ $\newline$ $13y = -26$
Find Value of y: Divide both sides by $13$ to find the value of $y$ . $\newline$ $y = \frac{-26}{13}$ $\newline$ $y = -2$
Substitute for x: Substitute the value of $y$ back into the second equation to solve for $x$ . $x = 3(-2) + 1$
Calculate x: Calculate the value of x. $\newline$ $x = -6 + 1$ $\newline$ $x = -5$