Solve the system of equations. {:[2x+7y=3],[x=-4y],[x=◻],[y=◻]:}

Solve second equation for x: Solve the second equation for x. Given x = -4y, we can use this to substitute for x in the first equation.Substitute x into first equation: Substitute x = -4y into the first equation. The first equation is 2x + 7y = 3. Substituting x gives us: 2(-4y) + 7y = 3 -8y + 7y = 3Combine like terms and solve for y: Combine like terms and solve for y. -8y + 7y = 3 simplifies to -y = 3. Multiplying both sides by -1 gives us y = -3.Substitute y back into second equation: Substitute y = -3 back into the second equation to find x. x = -4y x = -4(-3) x = 12Write solution as ordered pair: Write the solution as an ordered pair. We found x = 12 and y = -3, so the solution is (12, -3).

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Solve the system of equations.

{:[2x+7y=3],[x=-4y],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} 2 x+7 y=3 \\ x=-4 y \\ x=\square \\ y=\square \end{array}$

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Algebra 1

Solve a system of equations using substitution

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Q. Solve the system of equations.

\newline

\begin{array}{l} 2 x+7 y=3 \\ x=-4 y \\ x=\square \\ y=\square \end{array}

Solve second equation for $x$ : Solve the second equation for $x$ . $\newline$ Given $x = -4y$ , we can use this to substitute for $x$ in the first equation.
Substitute $x$ into first equation: Substitute $x = -4y$ into the first equation. $\newline$ The first equation is $2x + 7y = 3$ . Substituting $x$ gives us: $\newline$ $2(-4y) + 7y = 3$ $\newline$ $-8y + 7y = 3$
Combine like terms and solve for $y$ : Combine like terms and solve for $y$ . $\newline$ $-8$ y + $7$ y = $3$ simplifies to $-y =$ $3$ . $\newline$ Multiplying both sides by $-1$ gives us $y =$ $-3$ .
Substitute $y$ back into second equation: Substitute $y = -3$ back into the second equation to find $x$ .
$x = -4y$
$x = -4(-3)$
$x = 12$
Write solution as ordered pair: Write the solution as an ordered pair. $\newline$ We found $x = 12$ and $y = -3$ , so the solution is $(12, -3)$ .