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Solve the system of equations.

{:[12 x-5y=-20],[y=x+4],[x=◻],[y=◻]:}

Solve the system of equations.\newline12x5y=20y=x+4x=y= \begin{array}{l} 12 x-5 y=-20 \\ y=x+4 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline12x5y=20y=x+4x=y= \begin{array}{l} 12 x-5 y=-20 \\ y=x+4 \\ x=\square \\ y=\square \end{array}
  1. Substitute Equations: Substitute the second equation into the first equation.\newlineWe have the system of equations:\newline12x5y=2012x - 5y = -20\newliney=x+4y = x + 4\newlineSubstitute yy from the second equation into the first equation to eliminate yy and solve for xx.\newline12x5(x+4)=2012x - 5(x + 4) = -20
  2. Distribute and Combine Terms: Distribute and combine like terms.\newline12x5x20=2012x - 5x - 20 = -20\newlineCombine like terms:\newline(12x5x)20=20(12x - 5x) - 20 = -20\newline7x20=207x - 20 = -20
  3. Solve for x: Solve for x.\newlineAdd 2020 to both sides of the equation to isolate the xx term.\newline7x20+20=20+207x - 20 + 20 = -20 + 20\newline7x=07x = 0\newlineNow, divide both sides by 77 to solve for xx.\newlinex=0/7x = 0 / 7\newlinex=0x = 0
  4. Substitute xx to Solve yy: Substitute the value of xx into the second equation to solve for yy. We have x=0x = 0 and the second equation y=x+4y = x + 4. Substitute x=0x = 0 into the second equation: y=0+4y = 0 + 4 y=4y = 4

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