Solve the system of equations. {:[-10 x+3y=5],[x=y-4],[x=◻],[y=◻]:}

Solve second equation for x: Solve the second equation for x. The second equation is x = y - 4. We can use this expression for x to substitute into the first equation.Substitute x into first equation: Substitute x = y - 4 into the first equation. The first equation is -10x + 3y = 5. Replace x with y - 4 to get: -10(y - 4) + 3y = 5Distribute and combine like terms: Distribute -10 and combine like terms. -10y + 40 + 3y = 5 -7y + 40 = 5Isolate y: Isolate y. Subtract 40 from both sides to get: -7y = 5 - 40 -7y = -35Solve for y: Solve for y. Divide both sides by -7 to find y: y = -35 / -7 y = 5Substitute y back into second equation: Substitute y back into the second equation to find x. Now that we know y = 5, we can substitute it back into the equation x = y - 4 to find x: x = 5 - 4 x = 1Write solution as ordered pair: Write the solution as an ordered pair. The solution to the system of equations is x = 1 and y = 5, so the ordered pair is (1, 5).

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Solve the system of equations.

{:[-10 x+3y=5],[x=y-4],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -10 x+3 y=5 \\ x=y-4 \\ x=\square \\ y=\square \end{array}$

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Algebra 1

Solve a system of equations using substitution

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Q. Solve the system of equations.

\newline

\begin{array}{l} -10 x+3 y=5 \\ x=y-4 \\ x=\square \\ y=\square \end{array}

Solve second equation for x: Solve the second equation for x. $\newline$ The second equation is $x = y - 4$ . We can use this expression for $x$ to substitute into the first equation.
Substitute $x$ into first equation: Substitute $x = y - 4$ into the first equation. $\newline$ The first equation is $-10x + 3y = 5$ . Replace $x$ with $y - 4$ to get: $\newline$ $-10(y - 4) + 3y = 5$
Distribute and combine like terms: Distribute $-10$ and combine like terms. $-10y + 40 + 3y = 5$ $-7y + 40 = 5$
Isolate y: Isolate $y$ .
Subtract $40$ from both sides to get:
$-7y = 5 - 40$
$-7y = -35$
Solve for y: Solve for y. $\newline$ Divide both sides by $-7$ to find $y$ : $\newline$ $y = \frac{-35}{-7}$ $\newline$ $y = 5$
Substitute $y$ back into second equation: Substitute $y$ back into the second equation to find $x$ .
Now that we know $y = 5$ , we can substitute it back into the equation $x = y - 4$ to find $x$ :
$x = 5 - 4$
$x = 1$
Write solution as ordered pair: Write the solution as an ordered pair. $\newline$ The solution to the system of equations is $x = 1$ and $y = 5$ , so the ordered pair is $(1, 5)$ .