Solve for x. Enter the solutions from least to greatest. -x^(2)-8=-33 lesser x= greater x=

Rewrite equation to isolate x^2: First, let's rewrite the equation to isolate the x^2 term on one side. -x^2 - 8 = -33 Add 8 to both sides to get: -x^2 = -33 + 8 -x^2 = -25Get rid of negative sign: Now, we need to get rid of the negative sign in front of x^2. We can do this by multiplying both sides of the equation by -1. -x^2 * -1 = -25 * -1 x^2 = 25Take square root of both sides: Next, we take the square root of both sides to solve for x. Remember that taking the square root of a number gives us two solutions: one positive and one negative. √x^2 = ±√25 x = ±5Two solutions for x: We now have two solutions for x. The lesser value is -5 and the greater value is 5. lesser x = -5 greater x = 5

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Solve for
x.
Enter the solutions from least to greatest.

-x^(2)-8=-33
lesser
x=
greater
x=

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $-x^{2}-8=-33$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Math Problems

Algebra 1

Evaluate recursive formulas for sequences

Full solution

Q. Solve for

x

\newline

Enter the solutions from least to greatest.

\newline

-x^{2}-8=-33

\newline

lesser

x=

\newline

greater

x=

Rewrite equation to isolate $x^2$ : First, let's rewrite the equation to isolate the $x^2$ term on one side. $\newline$ $-x^2 - 8 = -33$ $\newline$ Add $8$ to both sides to get: $\newline$ $-x^2 = -33 + 8$ $\newline$ $-x^2 = -25$
Get rid of negative sign: Now, we need to get rid of the negative sign in front of $x^2$ . We can do this by multiplying both sides of the equation by $-1$ . $\newline$ $-x^2 \times -1 = -25 \times -1$ $\newline$ $x^2 = 25$
Take square root of both sides: Next, we take the square root of both sides to solve for $x$ . Remember that taking the square root of a number gives us two solutions: one positive and one negative. $\newline$ $\sqrt{x^2} = \pm\sqrt{25}$ $\newline$ $x = \pm5$
Two solutions for x: We now have two solutions for x. The lesser value is $-5$ and the greater value is $5$ . $\newline$ lesser $x = -5$ $\newline$ greater $x = 5$