Solve for x. Enter the solutions from least to greatest. Round to two decimal places. (x+8)^(2)-2=0 lesser x= greater x=

Write and set equation: Write down the given equation and set it equal to zero. (x+8)² - 2 = 0Isolate squared term: Add 2 to both sides of the equation to isolate the squared term. (x+8)² = 2Solve for x+8: Take the square root of both sides of the equation to solve for x+8. x+8 = ±√2Solve for x: Solve for x by subtracting 8 from both sides of the equation for both the positive and negative square root. x = -8 + √2 (lesser value) x = -8 - √2 (greater value)Calculate numerical values: Calculate the numerical values of x to two decimal places. x ≈ -8 + 1.41 (since √2 ≈ 1.41) x ≈ -6.59 (lesser value) x ≈ -8 - 1.41 x ≈ -9.41 (greater value)Correct order of solutions: Correct the order of the solutions from least to greatest. The lesser value is -9.41 and the greater value is -6.59.

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Solve for
x. Enter the solutions from least to greatest.
Round to two decimal places.

(x+8)^(2)-2=0
lesser
x=
greater
x=

Solve for $x$ . Enter the solutions from least to greatest. $\newline$ Round to two decimal places. $\newline$ $(x+8)^{2}-2=0$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Algebra 2

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Full solution

Q. Solve for

x

. Enter the solutions from least to greatest.

\newline

Round to two decimal places.

\newline

(x+8)^{2}-2=0

\newline

lesser

x=

\newline

greater

x=

Write and set equation: Write down the given equation and set it equal to zero. $(x+8)^2 - 2 = 0$
Isolate squared term: Add $2$ to both sides of the equation to isolate the squared term. $\newline$ $(x+8)^2 = 2$
Solve for $x+8$ : Take the square root of both sides of the equation to solve for $x+8$ . $\newline$ $x+8 = \pm\sqrt{2}$
Solve for x: Solve for x by subtracting $8$ from both sides of the equation for both the positive and negative square root. $\newline$ $x = -8 + \sqrt{2}$ (lesser value) $\newline$ $x = -8 - \sqrt{2}$ (greater value)
Calculate numerical values: Calculate the numerical values of $x$ to two decimal places. $x \approx -8 + 1.41 \quad (\text{since } \sqrt{2} \approx 1.41)$ $x \approx -6.59 \quad (\text{lesser value})$ $x \approx -8 - 1.41$ $x \approx -9.41 \quad (\text{greater value})$
Correct order of solutions: Correct the order of the solutions from least to greatest. $\newline$ The lesser value is $-9.41$ and the greater value is $-6.59$ .