Solve for x. Enter the solutions from least to greatest. 3x^(2)+4=436 lesser x= greater x=

Isolate quadratic term: First, we need to isolate the quadratic term by subtracting 4 from both sides of the equation. 3x^2 + 4 - 4 = 436 - 4 3x^2 = 432Divide by 3: Next, we divide both sides of the equation by 3 to solve for x^2. 3x^2 / 3 = 432 / 3 x^2 = 144Take square root: Now, we take the square root of both sides to solve for x. Remember that taking the square root gives us both a positive and a negative solution. √x^2 = ±√144 x = ±12List solutions: We have two solutions for x, which are x = 12 and x = -12. We need to list them from least to greatest. lesser x = -12 greater x = 12

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Solve for
x.
Enter the solutions from least to greatest.

3x^(2)+4=436
lesser
x=
greater
x=

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $3 x^{2}+4=436$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Math Problems

Algebra 1

Evaluate recursive formulas for sequences

Full solution

Q. Solve for

x

\newline

Enter the solutions from least to greatest.

\newline

3 x^{2}+4=436

\newline

lesser

x=

\newline

greater

x=

Isolate quadratic term: First, we need to isolate the quadratic term by subtracting $4$ from both sides of the equation. $\newline$ $3x^2 + 4 - 4 = 436 - 4$ $\newline$ $3x^2 = 432$
Divide by $3$ : Next, we divide both sides of the equation by $3$ to solve for $x^2$ . $\newline$ $\frac{3x^2}{3} = \frac{432}{3}$ $\newline$ $x^2 = 144$
Take square root: Now, we take the square root of both sides to solve for x. Remember that taking the square root gives us both a positive and a negative solution. $\newline$ $\sqrt{x^2} = \pm\sqrt{144}$ $\newline$ $x = \pm12$
List solutions: We have two solutions for x, which are $x = 12$ and $x = -12$ . We need to list them from least to greatest. $\newline$ lesser $x = -12$ $\newline$ greater $x = 12$