Solve for x. -9x+5 = -(4)/(3) (B) x = -(4)/(3) (D) There are no solutions (E) All values of x are solutions

Solve first inequality: Solve the first inequality -9x + 5 ≤ 17. Subtract 5 from both sides to isolate the term with x. -9x + 5 - 5 ≤ 17 - 5 -9x ≤ 12 Now, divide both sides by -9. Remember that dividing by a negative number reverses the inequality sign. -9x / -9 ≥ 12 / -9 x ≥ -4/3Solve second inequality: Solve the second inequality 13x + 25 ≤ -1. Subtract 25 from both sides to isolate the term with x. 13x + 25 - 25 ≤ -1 - 25 13x ≤ -26 Now, divide both sides by 13. 13x / 13 ≤ -26 / 13 x ≤ -2Combine solutions: Combine the solutions from Step 1 and Step 2. The solution to the system of inequalities is the union of the individual solutions because the original problem uses the word ＂OR＂. So, the solution set is x ≥ -4/3 OR x ≤ -2.

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Solve for
x.

-9x+5 <= 17quad OR
quad13 x+25 <= -1
Choose 1 answer:
(A)
x <= -2 or
x >= -(4)/(3)
(B)
x <= -2
(C)
x >= -(4)/(3)
(D) There are no solutions
(E) All values of
x are solutions

Solve for $x$ . $\newline$ $-9 x+5 \leq 17 \quad$ OR $\quad 13 x+25 \leq-1$ $\newline$ Choose $1$ answer: $\newline$ (A) $x \leq-2$ or $x \geq-\frac{4}{3}$ $\newline$ (B) $x \leq-2$ $\newline$ (C) $x \geq-\frac{4}{3}$ $\newline$ (D) There are no solutions $\newline$ (E) All values of $x$ are solutions

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Math Problems

Precalculus

Solve rational equations

Full solution

Q. Solve for

x

\newline

-9 x+5 \leq 17 \quad

\quad 13 x+25 \leq-1

\newline

Choose

1

answer:

\newline

(A)

x \leq-2

x \geq-\frac{4}{3}

\newline

(B)

x \leq-2

\newline

(C)

x \geq-\frac{4}{3}

\newline

(D) There are no solutions

\newline

(E) All values of

x

are solutions

Solve first inequality: Solve the first inequality $-9x + 5 \leq 17$ . $\newline$ Subtract $5$ from both sides to isolate the term with $x$ . $\newline$ $-9x + 5 - 5 \leq 17 - 5$ $\newline$ $-9x \leq 12$ $\newline$ Now, divide both sides by $-9$ . Remember that dividing by a negative number reverses the inequality sign. $\newline$ $-\frac{9x}{-9} \geq \frac{12}{-9}$ $\newline$ $x \geq -\frac{4}{3}$
Solve second inequality: Solve the second inequality $13x + 25 \leq -1$ . $\newline$ Subtract $25$ from both sides to isolate the term with $x$ . $\newline$ $13x + 25 - 25 \leq -1 - 25$ $\newline$ $13x \leq -26$ $\newline$ Now, divide both sides by $13$ . $\newline$ $\frac{13x}{13} \leq \frac{-26}{13}$ $\newline$ $x \leq -2$
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