Solve. -7x+8-10x^(2)=7 Choose 1 answer: (A) x=(7+-sqrt89)/(-20) (B) x=(-9+-sqrt249)/(-12) (c) x=(2+-sqrt29)/(5) (D) x=-1,(7)/(10)

Rewriting the equation: First, we need to rewrite the equation in standard quadratic form, which is ax^2 + bx + c = 0. -7x + 8 - 10x^2 = 7 Move all terms to one side of the equation to set it equal to zero. -10x^2 - 7x + 8 - 7 = 0 -10x^2 - 7x + 1 = 0 Now we have a = -10, b = -7, and c = 1.Using the quadratic formula: Next, we will use the quadratic formula to find the solutions for x. The quadratic formula is x = (-b ± sqrt(b^2 - 4ac)) / (2a). Substitute a = -10, b = -7, and c = 1 into the formula. x = (-(-7) ± sqrt((-7)^2 - 4(-10)(1))) / (2(-10)) x = (7 ± sqrt(49 + 40)) / (-20) x = (7 ± sqrt(89)) / (-20)Matching the correct answer: Now we have the solutions in the form of the quadratic formula. We can see that the correct answer matches option (A): x = (7 ± sqrt(89)) / (-20)

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Solve.

-7x+8-10x^(2)=7
Choose 1 answer:
(A)
x=(7+-sqrt89)/(-20)
(B)
x=(-9+-sqrt249)/(-12)
(c)
x=(2+-sqrt29)/(5)
(D)
x=-1,(7)/(10)

Solve. $\newline$ $-7 x+8-10 x^{2}=7$ $\newline$ Choose $1$ answer: $\newline$ (A) $x=\frac{7 \pm \sqrt{89}}{-20}$ $\newline$ (B) $x=\frac{-9 \pm \sqrt{249}}{-12}$ $\newline$ (C) $x=\frac{2 \pm \sqrt{29}}{5}$ $\newline$ (D) $x=-1, \frac{7}{10}$

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Math Problems

Algebra 2

Solve a quadratic equation using the quadratic formula

Full solution

Q. Solve.

\newline

-7 x+8-10 x^{2}=7

\newline

Choose

1

answer:

\newline

(A)

x=\frac{7 \pm \sqrt{89}}{-20}

\newline

(B)

x=\frac{-9 \pm \sqrt{249}}{-12}

\newline

(C)

x=\frac{2 \pm \sqrt{29}}{5}

\newline

(D)

x=-1, \frac{7}{10}

Rewriting the equation: First, we need to rewrite the equation in standard quadratic form, which is $ax^2 + bx + c = 0$ . $\newline$ $-7x + 8 - 10x^2 = 7$ $\newline$ Move all terms to one side of the equation to set it equal to zero. $\newline$ $-10x^2 - 7x + 8 - 7 = 0$ $\newline$ $-10x^2 - 7x + 1 = 0$ $\newline$ Now we have $a = -10$ , $b = -7$ , and $c = 1$ .
Using the quadratic formula: Next, we will use the quadratic formula to find the solutions for x. The quadratic formula is $x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}$ . $\newline$ Substitute $a = -10$ , $b = -7$ , and $c = 1$ into the formula. $\newline$ $x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(-10)(1)}}}}{{2(-10)}}$ $\newline$ $x = \frac{{7 \pm \sqrt{{49 + 40}}}}{{-20}}$ $\newline$ $x = \frac{{7 \pm \sqrt{{89}}}}{{-20}}$
Matching the correct answer: Now we have the solutions in the form of the quadratic formula. We can see that the correct answer matches option (A): $\newline$ $x = \frac{7 \pm \sqrt{89}}{-20}$