Solve. -7x+1-10x^(2)=0 Choose 1 answer: (A) x=(7+-sqrt89)/(-20) (B) x=(-1+-sqrt73)/(9) (C) x=(-3+-sqrt105)/(-12) (D) x=(-9+-sqrt249)/(-12)

Write quadratic equation in standard form: Write the quadratic equation in standard form. The standard form of a quadratic equation is ax^2 + bx + c = 0. Rearrange the given equation to match this form. -10x^2 - 7x + 1 = 0 Here, a = -10, b = -7, and c = 1.Apply quadratic formula to find solutions: Apply the quadratic formula to find the solutions for x. The quadratic formula is x = (-b ± sqrt(b^2 - 4ac)) / (2a). Substitute a = -10, b = -7, and c = 1 into the formula. x = (-(-7) ± sqrt((-7)^2 - 4(-10)(1))) / (2(-10)) x = (7 ± sqrt(49 + 40)) / (-20)Simplify expression and solve for x: Simplify the expression under the square root and solve for x. x = (7 ± sqrt(49 + 40)) / (-20) x = (7 ± sqrt(89)) / (-20) This matches answer choice (A).

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Solve.

-7x+1-10x^(2)=0
Choose 1 answer:
(A)
x=(7+-sqrt89)/(-20)
(B)
x=(-1+-sqrt73)/(9)
(C)
x=(-3+-sqrt105)/(-12)
(D)
x=(-9+-sqrt249)/(-12)

Solve. $\newline$ $-7 x+1-10 x^{2}=0$ $\newline$ Choose $1$ answer: $\newline$ (A) $x=\frac{7 \pm \sqrt{89}}{-20}$ $\newline$ (B) $x=\frac{-1 \pm \sqrt{73}}{9}$ $\newline$ (C) $x=\frac{-3 \pm \sqrt{105}}{-12}$ $\newline$ (D) $x=\frac{-9 \pm \sqrt{249}}{-12}$

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Math Problems

Algebra 2

Solve a quadratic equation using the quadratic formula

Full solution

Q. Solve.

\newline

-7 x+1-10 x^{2}=0

\newline

Choose

1

answer:

\newline

(A)

x=\frac{7 \pm \sqrt{89}}{-20}

\newline

(B)

x=\frac{-1 \pm \sqrt{73}}{9}

\newline

(C)

x=\frac{-3 \pm \sqrt{105}}{-12}

\newline

(D)

x=\frac{-9 \pm \sqrt{249}}{-12}

Write quadratic equation in standard form: Write the quadratic equation in standard form. $\newline$ The standard form of a quadratic equation is $ax^2 + bx + c = 0$ . Rearrange the given equation to match this form. $\newline$ $-10x^2 - 7x + 1 = 0$ $\newline$ Here, $a = -10$ , $b = -7$ , and $c = 1$ .
Apply quadratic formula to find solutions: Apply the quadratic formula to find the solutions for $x$ . $\newline$ The quadratic formula is $x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}$ . $\newline$ Substitute $a = -10$ , $b = -7$ , and $c = 1$ into the formula. $\newline$ $x = \frac{{-(-7) \pm \sqrt{{(-7)^2 - 4(-10)(1)}}}}{{2(-10)}}$ $\newline$ $x = \frac{{7 \pm \sqrt{{49 + 40}}}}{{-20}}$
Simplify expression and solve for x: Simplify the expression under the square root and solve for x. $\newline$ $x = \frac{7 \pm \sqrt{49 + 40}}{-20}$ $\newline$ $x = \frac{7 \pm \sqrt{89}}{-20}$ $\newline$ This matches answer choice (A).