Identify Quadratic Equation: Now we have a quadratic equation in the form ax2+bx+c=0, where a=−6, b=−3, and c=6. We can solve this using the quadratic formula, x=2a−b±b2−4ac.
Apply Quadratic Formula: Now we can plug the values of a, b, and the discriminant into the quadratic formula.x=2×−6−(−3)±153x=−123±153
Simplify Square Root: Simplify the square root of the discriminant if possible. Since 153 is not a perfect square, we leave it as 153.x=−123±153
Simplify Fraction: Now we need to simplify the fraction by dividing the numerator by the denominator.x=−123±−12153x=4−1±−12153
Simplify Second Term: We can simplify the second term by dividing 153 by −12. x=(−41)±(−12153) x=(−41)±(−12153)
Write Possible Solutions: We can now write the two possible solutions for x.x=(−41)+(−153)/12 or x=(−41)−(−153)/12
Find Common Denominator: To match the answer choices, we need to find a common denominator for the two terms in each solution.x=(−3/12)−(153/12) or x=(−3/12)+(153/12)x=(−3−153)/12 or x=(−3+153)/12
Match Answer Choices: Now we can see that the solutions match one of the answer choices. x=(−3−153)/12 or x=(−3+153)/12This corresponds to answer choice (D) x=(1±17)/(−4) if we simplify 153 to 17∗9 and take out a factor of 3 from the square root. However, this simplification is incorrect because 153 cannot be simplified to 17∗9 as 153 is not a multiple of 9. Therefore, we have made a math error.
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