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Ruby can assemble 2 gift baskets by herself in 7 minutes. Emma can assemble 4 gift baskets by herself in 15 minutes. Ruby begins assembling gift baskets at 1:00 p.m., and Emma begins assembling gift baskets at 1:15 p.m. If they continue to work at the above rates, at what time will they finish the 
54^("th ") basket?
Choose 1 answer:
(A) 2:30 p.m.
(B) 
2:42p.m.
(c) 
2:45 p.m.
(D) 
3:00p.m.

Ruby can assemble 22 gift baskets by herself in 77 minutes. Emma can assemble 44 gift baskets by herself in 1515 minutes. Ruby begins assembling gift baskets at 1:001: 00 p.m.,\mathrm{p} . \mathrm{m}., and Emma begins assembling gift baskets at 1:15 1: 15 p.m.\mathrm{p} . \mathrm{m}. If they continue to work at the above rates, at what time will they finish the 54th  54^{\text {th }} basket?\newlineChoose 11 answer:\newline(A) 2:30 2: 30 p.m\mathrm{p} . \mathrm{m} .\newline(B) 2:42 2: 42 p.m\mathrm{p} . \mathrm{m} .\newline(C) 2:45 2: 45 p.m\mathrm{p} . \mathrm{m} .\newline(D) 3:00 3: 00 p.m\mathrm{p} . \mathrm{m} .

Full solution

Q. Ruby can assemble 22 gift baskets by herself in 77 minutes. Emma can assemble 44 gift baskets by herself in 1515 minutes. Ruby begins assembling gift baskets at 1:001: 00 p.m.,\mathrm{p} . \mathrm{m}., and Emma begins assembling gift baskets at 1:15 1: 15 p.m.\mathrm{p} . \mathrm{m}. If they continue to work at the above rates, at what time will they finish the 54th  54^{\text {th }} basket?\newlineChoose 11 answer:\newline(A) 2:30 2: 30 p.m\mathrm{p} . \mathrm{m} .\newline(B) 2:42 2: 42 p.m\mathrm{p} . \mathrm{m} .\newline(C) 2:45 2: 45 p.m\mathrm{p} . \mathrm{m} .\newline(D) 3:00 3: 00 p.m\mathrm{p} . \mathrm{m} .
  1. Determine Ruby's time per basket: Divide the total time by the number of baskets Ruby can assemble.\newline Ruby's time per basket =7minutes2baskets= \frac{7 \, \text{minutes}}{2 \, \text{baskets}} \newline =3.5minutes per basket=3.5 \, \text{minutes per basket}
  2. Determine Emma's time per basket: Divide the total time by the number of baskets Emma can assemble.\newline Emma's time per basket =15minutes4baskets= \frac{15 \, \text{minutes}}{4 \, \text{baskets}} \newline =3.75minutes per basket=3.75 \, \text{minutes per basket}
  3. Set up the equation: Let tt minutes have passed since 1:00p.m.1:00 \, \text{p.m.} for Ruby to assemble t3.5\frac{t}{3.5} baskets and for Emma to assemble t153.75\frac{t-15}{3.75} baskets. \newline Set up the equation to find the value of tt such that the total number of baskets assembled is 5454: \newline t3.5+t153.75=54\frac{t}{3.5} + \frac{t-15}{3.75} = 54
  4. Find the value of tt: Solve for tt to find the time it takes for Ruby and Emma to assemble 5454 baskets.\newline The least common denominator (LCD) of 3.53.5 and 3.753.75 is 13.12513.125. \newline 3.75(t)+3.5(t15)13.125=54\frac{3.75(t) + 3.5(t-15)}{13.125} = 54 \newline 3.75t+3.5t52.513.125=54\frac{3.75t + 3.5t-52.5}{13.125} = 54 \newline 7.25t52.5=708.757.25t-52.5 = 708.75 \newline 7.25t=761.257.25t = 761.25 \newline t=105minutest = 105 \, \text{minutes}
  5. Convert minutes to hours and minutes: 105105 minutes is 11 hour and 4545 minutes.
  6. Calculate the time they both will finish the 54th  54^{\text {th }} basket: Add the time Ruby started working to the total time to find the finishing time. Ruby started at 1:00p.m.1:00 \, \text{p.m.} and Emma started 1515 minutes later, so they will finish together at: \newline 1:00p.m.+1hour and45minutes=2:45p.m.1:00 \, \text{p.m.} + 1 \, \text{hour and} \, 45 \, \text{minutes} = 2:45 \, \text{p.m.} \newlineTherefore, Ruby and Emma will finish assembling the 54th  54^{\text {th }} basket at 2:45p.m.2:45 \, \text{p.m.}

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