Ruby can assemble 2 gift baskets by herself in 7 minutes. Emma can assemble 4 gift baskets by herself in 15 minutes. Ruby begins assembling gift baskets at 1:00p.m., and Emma begins assembling gift baskets at 1:15p.m. If they continue to work at the above rates, at what time will they finish the 54th basket?Choose 1 answer:(A) 2:30p.m.(B) 2:42p.m.(C) 2:45p.m.(D) 3:00p.m.
Q. Ruby can assemble 2 gift baskets by herself in 7 minutes. Emma can assemble 4 gift baskets by herself in 15 minutes. Ruby begins assembling gift baskets at 1:00p.m., and Emma begins assembling gift baskets at 1:15p.m. If they continue to work at the above rates, at what time will they finish the 54th basket?Choose 1 answer:(A) 2:30p.m.(B) 2:42p.m.(C) 2:45p.m.(D) 3:00p.m.
Determine Ruby's time per basket: Divide the total time by the number of baskets Ruby can assemble. Ruby's time per basket =2baskets7minutes=3.5minutes per basket
Determine Emma's time per basket: Divide the total time by the number of baskets Emma can assemble. Emma's time per basket =4baskets15minutes=3.75minutes per basket
Set up the equation: Let t minutes have passed since 1:00p.m. for Ruby to assemble 3.5t baskets and for Emma to assemble 3.75t−15 baskets. Set up the equation to find the value of t such that the total number of baskets assembled is 54: 3.5t+3.75t−15=54
Find the value of t: Solve for t to find the time it takes for Ruby and Emma to assemble 54 baskets. The least common denominator (LCD) of 3.5 and 3.75 is 13.125. 13.1253.75(t)+3.5(t−15)=5413.1253.75t+3.5t−52.5=547.25t−52.5=708.757.25t=761.25t=105minutes
Convert minutes to hours and minutes:105 minutes is 1 hour and 45 minutes.
Calculate the time they both will finish the 54th basket: Add the time Ruby started working to the total time to find the finishing time. Ruby started at 1:00p.m. and Emma started 15 minutes later, so they will finish together at: 1:00p.m.+1hour and45minutes=2:45p.m.Therefore, Ruby and Emma will finish assembling the 54th basket at 2:45p.m.
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